Answer:
78
Step-by-step explanation:
Evaluate 6 (2 x^2 - 5) where x = -3:
6 (2 x^2 - 5) = 6 (2×(-3)^2 - 5)
Hint: | Evaluate (-3)^2.
(-3)^2 = 9:
6 (2×9 - 5)
Hint: | Multiply 2 and 9 together.
2×9 = 18:
6 (18 - 5)
Hint: | Subtract 5 from 18.
| 1 | 8
- | | 5
| 1 | 3:
6×13
Hint: | Multiply 6 and 13 together.
6×13 = 78:
Answer: 78
the answer is a n b
Step-by-step explanation:
Answer:
Please check the attached figure!
Step-by-step explanation:
Part a)
Point A is located at the x-coordinate x=-4 and y-coordinate y=1.
Hence, the coordinates of point A = (-4, 1)
Part b)
Point B(3, -2) has been plotted and is shown in the attached figure.
It is clear from the attached diagram that point B is located at the x-coordinate x=3 and y-coordinate y=-2. Hence, the coordinates of point B = (3, -2)
Part C)
Point C has the same x-coordinate as point A i.e. x=-4 and the same y-coordinate as point B i.e. y=-2.
Hence, the coordinates of point C = (-4, -2). Point C is also plotted as shown in the diagram.
Answer:
Step-by-step explanation:
11
Answer:
C) . y=(1/10)x+3
Step-by-step explanation:
Given the equation of the line is y=-10x+8
It is in the form of y=mx+c where m is the slope of the line. Now on comparision we get m1=-10.
We knoew that two lines are perpendicular iff the product of their slopes is equal to -1.

the slope of the recquired line =
=
The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept
Given the y intercept of the recquired line (b)=3
The recquired line is
y=mx+b
y=(1/10)x+3