Up to 80% of doctors endorse this project uses Weasel Words<span>.
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Weasel Words are the statements that are intentionally ambiguous or misleading.
These words are commonly used<span> in advertising and in political statements to mislead.</span>
-2 = - x + x^2 -4 => x^2 - x - 4 + 2 = 0
x^2 - x - 2 = 0
a is the coefficient of x^2 => a = 1
b is the coefficient of x => b = - 1
c is the constant term => c = - 2
quadratic equation: [- b +/- √(b^2 - 4ac) ] / 2a =
= { 1 +/- √[ (-1)^2 - 4(1)(-2)] } / (2(1) = { 1 +/- √ (1 + 8) } / 2 = {1 +/- √9} / 2 =
= { 1 +/- 3} / 2
List of the first few prime numbers greater than 3:
5, 7, 11, 13, 17, 19, 23, 29
Now find the combination that you can multiply and still have a 2 digit number:
5 x 7 = 35
5 x 11 = 55
5 x 13 = 65
5 x 17 = 85
5 x 19 = 95
5 x 23 = 115 ( 3 digit number, can't use).
7 x 5 = 35
7 x 11 = 77
7 x 13 = 91
7 x 19 = 133 ( 3 digit number, can't use).
The largest 2 digit number would be 5 x 19 = 95
Answer:
We have the function:
r = -3 + 4*cos(θ)
And we want to find the value of θ where we have the maximum value of r.
For this, we can see that the cosine function has a positive coeficient, so when the cosine function has a maximum, also does the value of r.
We know that the meaximum value of the cosine is 1, and it happens when:
θ = 2n*pi, for any integer value of n.
Then the answer is θ = 2n*pi, in this point we have:
r = -3 + 4*cos (2n*pi) = -3 + 4 = 1
The maximum value of r is 7
(while you may have a biger, in magnitude, value for r if you select the negative solutions for the cosine, you need to remember that the radius must be always a positive number)
