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2 years ago

The midpoint of AB is M(1,4).if the coordinates of A are (-3,-6),what are the coordinates of B

Mathematics

1 answer:

boyakko [2]2 years ago

4 0

midpoint of AB (M)=(1,4)=(x,y)

COOrdinates of A=(-3,-6)=(X1,Y1)

coordinates of B=?

using midpoint formula,

X=(X1+X2/2)

or,1=(-3+X2/2)

or,2=-3+X2

or,2+3=X2

5=X2

Y=(Y1+Y2/2)

or,4=(-6+Y2/2)

or,4×2=-6+Y2

or,8+6=Y2

14=Y2

so,co-ordinates of B are(5,14).

plz mark me brainliest.

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Answer:

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(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

A = video components need repair within 1 year

B = electronic components need repair within 1 year

C = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events A, B and C are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

$=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278$

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

$=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277$

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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Answer:

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x + x + x = 3x ;

− 2 − 4 = −6 ;

So we have: "3x − 6" as the sum. ;
___________________________
The sum of three consecutive odd integers, in which "x" is the greatest integer; is: "3x − 6" .
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