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3 years ago

Help asap! 50 Points! 10 Questions!

1 answer:

3 0

Part 1) If a cylinder has a surface area of 36 square inches and its radius is 1.6 inches, how tall is the cylinder in inches? π = 3.14. Round to the nearest tenth.

we know that
surface area of the cylinder=2*area of the base+perimeter of the base*height

area of the base==pi*r²*h-----> 3.14*1.6²*h----> 8.0384*h in²

perimeter of the base=2*pi*r---> 2*3.14*1.6----> 10.048 in

surface area=36 in²
so
36=2*[8.0384*h]+10.048*h----> 36=26.1248*h
h=36/26.1248----> h=1.38 in------> h=1.4 in

the answer Part 1) is
h=1.4 in

Part 2) 2. A regular hexagonal pyramid has a base area of 29 in^2 and a lateral area of 210 in^2. What is the surface area of the hexagonal pyramid?

surface area of the hexagonal pyramid=2*area of base+lateral area
surface area of the hexagonal pyramid=2*29+210----> 268 in²

the answer part 2) is
surface area=268 in²

Part 3) What is the surface area of the following cylinder in square inches? Use π = 3.14 and round your answer to the nearest tenth.
Radius = 3.2 Height = 4.1
we know that
surface area of the cylinder=2*area of the base+perimeter of the base*height

area of the base==pi*r²*h-----> 3.14*3.2²*4.1----> 131.83 in²

perimeter of the base=2*pi*r---> 2*3.14*3.2----> 20.096in

surface area=2*131.83+20.096*4.1------> 346.05 in²-----> 346.1 in²

the answer Part 3)
surface area=346.1 in²

part 4)A cube has surface area of 150 in^2. How long is each side of the cube?

we know that
surface area of cube=6*b²
where b is the length side of the cube
SA=6*b²------> b=√SA/6------> b=√150/6-----> √25----> b=5 in

the answer Part 4) is
b=5 in

Part 5) A cube has sides that are 3 in. long. What is the surface area of the cube?
we know that
surface area of cube=6*b²
where b is the length side of the cube
b=3 in
so
SA=6*3²----> 54 in²

the answer Part 5) is
SA=54 in²

Part 6) What is the surface area of this box?
Height = 3.5 Length = 6 width = 3

surface area of the box=2*area of the base+perimeter of base*height

area of the base=6*3----> 18 ft²

perimeter of the base=2*[6+3]----> 18 ft
height=3.5 ft

surface area of the box=2*18+18*3.5----> 99 ft²

the answer Part 6) is
SA=99 ft²

Part 7) If a cylinder has a surface area of 59 square inches and its radius is 2.1 inches, how tall is the cylinder in inches? Use π = 3.14. Round to the nearest tenth


we know that
surface area of the cylinder=2*area of the base+perimeter of the base*height

area of the base==pi*r²*h-----> 3.14*2.1²*h----> 13.8474*h in²

perimeter of the base=2*pi*r---> 2*3.14*2.1----> 13.188 in

surface area=59 in²
so
59=2*[13.8474*h]+13.188*h----> 59=40.8828*h
h=59/40.8828----> h=1.44 in------> h=1.4 in

the answer Part 7) is
h=1.4 in

Part 8) What is the surface area of the cone below, rounded to the nearest tenth? Use π = 3.14.
Height = 12 Radius = 5
surface area of the cone=pi*r²+pi*r*l
r=5 in
h=12 in
l=slant height
l²=r²+h²----> l²=5²+12²----> l²=169-----> l=13 in

surface area of the cone=3.14*5²+3.14*5*13-----> 282.6 in²

the answer Part 8) is
SA=282.6 in²

Part 9) A square pyramid has a surface area of 202 ft^2 and a base area of 53 ft^2. What is the lateral area of the pyramid?

we know that
surface area=area of the base+lateral area
lateral area=surface area-area of the base
lateral area=202-53----> 149 ft²

the answer Part 9) is
LA=149 ft²

Part 10)What is the surface area of the cone below, rounded to the nearest tenth? Use π = 3.14
Radius = 2 Height = 4

surface area of the cone=pi*r²+pi*r*l
r=2 cm
h=4 cm
l=slant height
l²=r²+h²----> l²=2²+4²----> l²=20-----> l=4.47 cm

surface area of the cone=3.14*2²+3.14*2*4.47-----> 40.63 cm²

the answer Part 10) is
SA=40.6 cm²

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a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

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Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

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2 years ago

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Answer:

Step-by-step explanation:

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