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Marat540 [252]
3 years ago
11

Use a common denominator to find negative 2/3 plus negative 4/5

Mathematics
2 answers:
leonid [27]3 years ago
5 0
-10/15 + -12/15 = -1 6/15. -2/3 becomes -10/15 when multiplied by 5. -4/5 becomes -12/15 when multiplied by 3.
SIZIF [17.4K]3 years ago
4 0

answer:

\frac{22}{15} or 1 \frac{7}{15}

step-by-step explanation:

a common denominator between 3 and 5 is 15

first to get our denominator in the fraction \frac{2}{3} to 15 we need to multiply by 5 so 2 × 5 = 10 and 3 × 5 = 15

this makes our new fraction \frac{10}{15}

now we need to get our denominator in the fraction \frac{4}{5} to 15 so we need to multiply by 3 so 4 × 3 = 12 and 5 × 3 = 12

this makes our new fraction \frac{12}{15}

our new equation with common denominators is now \frac{10}{15} + \frac{12}{15} = coming out to be \frac{22}{15}

to make this into a mixed fraction we know 22 only goes into 15 once with 7 left over so our mixed fraction is 1 \frac{7}{15}

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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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Answer:

Step-by-step explanation:

Since the squares have areas of 32u^2. The side lengths are

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