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Lunna [17]
3 years ago
9

IIIIIII-PLEASE HELP-IIIIII THERE ARE TWO QUESTIONS (ILL GIVE BRAINLIST)

Physics
2 answers:
TiliK225 [7]3 years ago
5 0

Answer:

the answers should be B and D

satela [25.4K]3 years ago
3 0

Answer:

Q. 1 is transform

Q. 2 is plates move past each other sideways

Explanation:

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A box slides down a frictionless incline, gaining speed. The work done by the normal force n is _______.
jeka57 [31]

The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

<h3>What is normal force?</h3>

The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.

This force is applied by the solid bodies on each other in order to prevent the passing through each other.

A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.

  • The body is gaining the speed, which means there is a change in kinetic energy.
  • The change in kinetic energy is equal to the work done.
  • The friction force is the product of coefficient of the friction and normal force.
  • The friction force for the given case is zero. Thus, the normal force must be equal to the zero.

Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

Learn more about the normal force here;

brainly.com/question/10941832

7 0
2 years ago
Read 2 more answers
starting at a position of 0 m, if the man is moving at a constant velocity of 2 m/s, it will take seconds for him to reach a pos
Harman [31]

The calculated time is 6 seconds.

Time is defined by physicists as the flow of events from the past through the present and into the future. In essence, a system is timeless if it is unchanging. When describing events that take place in three-dimensional space, time can be thought of as the fourth dimension of reality. Even if time isn't directly connected to energy, it is undoubtedly connected to many other components of energy. For instance, the movement of energy across the universe can affect the direction of time (from the past to the future).

V= 2 m/s

d=12 m

t=?

we know that velocity=displacement / time

time= displacement / velocity

= 12/2

=6 seconds

the calculated time is 6 seconds.

Learn more about time here-

brainly.com/question/28050940

#SPJ4

4 0
1 year ago
An electron is projected with an initial speed vi = 4.60 × 105 m/s directly toward a very distant proton that is at rest. Becaus
frutty [35]

Answer:

2.99\times 10^{-19}\ m

Explanation:

<u>Given:</u>

  • u = initial velocity of the electron = 4.60\times 10^5\ m/s
  • v = final velocity of the electron = 3u
  • x = initial position of the electron from the proton = very distant =  \infty

<u>Assume:</u>

  • m = mass of an electron = 9.1\times10^{-31}\ kg
  • e = magnitude of charge on an electron = 1.6\times10^{-19}\ C
  • p = magnitude of charge on an proton = 1.6\times10^{-19}\ C
  • k = Boltzmann constant = 9\times 10^9\ Nm^2/C^2
  • y = final position of the electron from the proton
  • \Delta K = change in kinetic energy of the electron
  • W = work done by the electrostatic force
  • F = electrostatic force
  • r = instantaneous distance of the electron from the proton

Let us first calculate the work done by the electrostatic force.

W=\int Fdr\\\Rightarrow W = \int \dfrac{kep}{r^2}dr\\\Rightarrow W = kep\int \dfrac{1}{r^2}dr\\\Rightarrow W = kep\left | \dfrac{1}{r} \right |_{y}^{x}\\\Rightarrow W = kep\left ( \dfrac{1}{x}-\dfrac{1}{y} \right )\\\Rightarrow W = kep\left ( \dfrac{1}{x}-\dfrac{1}{\infty} \right )\\\Rightarrow W =\dfrac{kep}{x}

Using the principle of the work-energy theorem,

As only the electrostatic force is assumed to act between the two charges, the kinetic energy change of the electron will be equal to the work done by the electrostatic force on the electron due to proton.

\therefore \Delta K = W\\\Rightarrow \dfrac{1}{2}m(v^2-u^2)= \dfrac{kep}{x}\\\Rightarrow \dfrac{1}{2}m((3u)^2-u^2)= \dfrac{kep}{x}\\\Rightarrow \dfrac{1}{2}m(8u^2)= \dfrac{kep}{x}\\\Rightarrow x= \dfrac{2kep}{8mu^2}\\\Rightarrow x= \dfrac{2\times 9\times 10^9\times 1.6\times10^{-19}\times 1.6\times10^{-19}}{8\times 9.1\times10^{-31}\times (4.60\times 10^5)^2}\\\Rightarrow x=2.99\times 10^{-10}\ m\leq

Hence, the electron is at a distance of 2.99\times 10^{-10}\ m when the electron instantaneously has speed of three times the initial speed.

8 0
4 years ago
015 10.0 points
Salsk061 [2.6K]

Answer:

20.996 m

Explanation:

Given:

Initial velocity, u=0 \textrm{ m/s}

Final velocity, v=12.4062 \textrm{ m/s}

Total time taken, t_{Total} = 7.13 s.

∴ Acceleration is given as,

a=\frac{v-u}{t_{Total}}=\frac{12.4062-0}{7.13}=1.74 m/s²

Now, using Newton's equation of motion, we find the displacement.

Displacement is given as:

s=ut+\frac{1}{2} at^{2}

Plug in 0 for u, 4.91257 for t and 1.74 for a. Solve for s.

This gives,

s=0+\frac{1}{2} \times 1.74 \times (4.91257)^{2}=20.996 \textrm{ m}

Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.

7 0
3 years ago
What is the acceleration due to gravity on Mars?
Leona [35]

The acceleration of gravity on Mars is about 3.7 m/s². (b)

So anything located on the surface of Mars weighs about 38% of what it would weigh if it were on Earth.

8 0
4 years ago
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