The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.
<h3>What is normal force?</h3>
The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.
This force is applied by the solid bodies on each other in order to prevent the passing through each other.
A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.
- The body is gaining the speed, which means there is a change in kinetic energy.
- The change in kinetic energy is equal to the work done.
- The friction force is the product of coefficient of the friction and normal force.
- The friction force for the given case is zero. Thus, the normal force must be equal to the zero.
Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.
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The calculated time is 6 seconds.
Time is defined by physicists as the flow of events from the past through the present and into the future. In essence, a system is timeless if it is unchanging. When describing events that take place in three-dimensional space, time can be thought of as the fourth dimension of reality. Even if time isn't directly connected to energy, it is undoubtedly connected to many other components of energy. For instance, the movement of energy across the universe can affect the direction of time (from the past to the future).
V= 2 m/s
d=12 m
t=?
we know that velocity=displacement / time
time= displacement / velocity
= 12/2
=6 seconds
the calculated time is 6 seconds.
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Answer:
20.996 m
Explanation:
Given:
Initial velocity, 
Final velocity, 
Total time taken, 
s.
∴ Acceleration is given as,
m/s²
Now, using Newton's equation of motion, we find the displacement.
Displacement is given as:
Plug in 0 for 
, 4.91257 for 
and 1.74 for 
. Solve for 
.
This gives,
Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.
The acceleration of gravity on Mars is about 3.7 m/s². (b)
So anything located on the surface of Mars weighs about 38% of what it would weigh if it were on Earth.
= final velocity of the electron =
= initial position of the electron from the proton = very distant =
= mass of an electron =
= magnitude of charge on an electron =
= magnitude of charge on an proton =
= Boltzmann constant =
= final position of the electron from the proton
= change in kinetic energy of the electron
= work done by the electrostatic force
= electrostatic force
= instantaneous distance of the electron from the proton