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Mice21 [21]
3 years ago
13

What would happen to the brightness of the bulb in the following circuit as I increase the resistance of the variable resistor?

Explain your answer

Physics
1 answer:
Margarita [4]3 years ago
4 0
As you crank the variable resistor to higher resistance, the total current in the loop decreases.  The power dissipated by the light bulb ... the heat and brightness it produces ... depend directly on the current through it, so they decrease too.  Your circuit is a perfect incandescent light dimmer circuit.
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What is the ionisation energy of an atom
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Explanation:

its the minimum amount of energy required to remove the most loosely bound electron

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A student examines a 20-meter long rectangular stream channel and takes the following measurements: width of stream = 4 meters,
Scrat [10]

Answer:

The discharge of the stream at this location is 40 cubic meters per second.

Explanation:

The discharge is the volume flow rate of the water in the stream. For this purpose we can use the following formula:

Discharge = Volume Flow Rate = (Cross-Sectional Area)(Velocity of Stream)

Volume Flow Rate = (Width of Stream)(Depth of Stream)(Velocity of Stream)

Volume Flow Rate = (4 meters)(2 meters)(5 meters per second)

<u>Volume Flow Rate = 40 cubic meters per second</u>

Therefore, the discharge of the stream at this location is found to be <u>40 cubic meters per second</u>

This result shows that 40 cubic meters volume of water passes or discharges through this point in a time of one second. Hence, this is called the volume flow rate or the discharge of the stream.

3 0
3 years ago
Two 10 kg pucks head straight towards each other with velocities of 10 m/s and -20 m/s. They collide and stick together. Calcula
RUDIKE [14]

The final velocity of the two pucks is -5 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum.

In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:

m_1 u_1 + m_2 u_2 = (m_1 +m_2)v

where

m_1 = m_2 = m = 10 kg is the mass of each puck

u_1 = 10 m/s is the initial velocity of the 1st puck

u_2 = -20 m/s is the initial velocity of the 2nd puck

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Re-arranging the equation and solving for v, we find:

mu_1 + mu_2 = (m+m)v\\u_1 + u_2 = 2v\\v=\frac{u_1+u_2}{2}=\frac{10-20}{2}=-5 m/s

Learn more about momentum:

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8 0
2 years ago
Please solve this question ​
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88200 Pa

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now,

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8 0
2 years ago
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timofeeve [1]

Answer:

A.

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NEAR THE CENTER OF TECTONIC PLATES.

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