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Vika [28.1K]
4 years ago
14

Jennifer, who has a mass of 48.0 kg, is riding at 40.2 m/s in her red sports car when she must suddenly slam on the brakes. An a

ir bag deploys in the car. She strikes the air bag, bringing her body to a stop in 0.56 s. What average force does the air bag exert on her
Physics
2 answers:
andre [41]4 years ago
6 0

Answer:

F = 3,445.71 N

Explanation:

Finding the deceleration (a):

a = \frac{u - v}{t}

initial velocity = u = 40.2 m/s

final velocity = v = 0 m/s

a = 40.2/0.56 = 71.785 m/s^2

Now, Finding the force:

F = ma

mass = m = 48.0 kg

a = 71.785 m/s^2

the force is found to be 3,445.71 N

Bogdan [553]4 years ago
3 0

Answer:

F = 3445.714\,N

Explanation:

The system can be modelled appropriately by the use of the Principle of Momentum Conservation and Impact Theorem:

(48\,kg)\cdot (40.2\,\frac{m}{s} ) - F\cdot (0.56\,s) = 0\,\frac{kg\cdot m}{s}

The average force exerted on her:

F = 3445.714\,N

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If water is leaking from a certain tank at a constant rate, is it leaking at a rate that is greater than 12 liters per hour?(1 l
Margarita [4]

Answer:

Yes  it is possible because 3.33 is greater than 2.

Explanation:

Given that,

1 liter = 1000 milliliters

Suppose water is leaking from the tank at a rate that is greater than 2 milliliters per second.

We need to change the unit in ml/s

12 lit/hr=\dfrac{12000}{3600}

12 lit/hr=3.33\ ml/s

Hence, Yes  it is possible because 3.33 is greater than 2.

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An important difference between waves and classical particles is that A. waves cannot interfere. B. particles cannot interfere.
pishuonlain [190]
<span>C. waves can only interfere destructively. </span>
5 0
3 years ago
Ple can someone help me to answer this question
ra1l [238]

The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

<h3 /><h3>A sketch of the uniform stick and the mass</h3>

The sketch of the uniform stick and the mass will be two based on the given statement.

<h3>when the uniform stick balances on knife at 10 cm from one end;</h3>

-------------------------------------------------------  

↓      10cm           Δ       (L - 10 cm)         ↓

200g                                                      M

<h3>When the knife edge is moved 5 cm further</h3>

|---------------15 cm-----------------|

-----------------------------------------------------------------------

              ↓      8.75 cm           Δ       (L - 15 cm)         ↓

          200g                                                               M

From the first diagram, apply principle of moment;

200(10) = M(L - 10) ------- (1)

From the second diagram, apply principle of moment;

200(8.75) = M(L - 15)   ------- (2)

From equation (1); M = (2000) / (L - 10)

From equation (2); M = (1750) / (L - 15)

Solve (1) and (2);

(2000) / (L - 10) = (1750) / (L - 15)

1750(L - 10) = 2000(L - 15)

L - 10 = 2000/1750(L - 15)

L - 10 = 1.143(L - 15)

L - 10 = 1.143L - 17.14

17.14 - 10 = 1.143L - L

7.14 = 0.143L

L = 7.14/0.143

L = 50 cm

<h3>Mass of the uniform stick</h3>

M = (2000) / (50 - 10)

M = 50 g

Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

Learn more about length of meter stick here: brainly.com/question/17225736

#SPJ1

8 0
2 years ago
He blocked his man using a force of 23 N moving him backward 2 meters ,how much work did he do?
Paul [167]

Answer:

work done = force x distance

Explanation:

F = 23 N

D = 2m

W = 23 * 2 = 46 J

6 0
4 years ago
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