Answer:
a. 572Btu/s
b.0.1483Btu/s.R
Explanation:
a.Assume a steady state operation, KE and PE are both neglected and fluids properties are constant.
From table A-3E, the specific heat of water is
, and the steam properties as, A-4E:

Using the energy balance for the system:

Hence, the rate of heat transfer in the heat exchanger is 572Btu/s
b. Heat gained by the water is equal to the heat lost by the condensing steam.
-The rate of steam condensation is expressed as:

Entropy generation in the heat exchanger could be defined using the entropy balance on the system:

Hence,the rate of entropy generation in the heat exchanger. is 0.1483Btu/s.R
Question is from B to C
Answer: (b) 1.5m/s
x1=3m, x2=9m
t1=1s, t2=5s
Displacement, ∆x=(9-3)m=6m
Time elapsed, ∆t=(5-1)s=4s
So average velocity v =∆x/∆t=6/4=1.5m/s
Answer:
The pressure and maximum height are
and 161.22 m respectively.
Explanation:
Given that,
Diameter = 3.00 cm
Exit diameter = 9.00 cm
Flow = 40.0 L/s²
We need to calculate the pressure
Using Bernoulli effect

When two point are at same height so ,
....(I)
Firstly we need to calculate the velocity
Using continuity equation
For input velocity,




For output velocity,


Put the value into the formula



(b). We need to calculate the maximum height
Using formula of height

Put the value into the formula



Hence, The pressure and maximum height are
and 161.22 m respectively.