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Vika [28.1K]
3 years ago
14

Jennifer, who has a mass of 48.0 kg, is riding at 40.2 m/s in her red sports car when she must suddenly slam on the brakes. An a

ir bag deploys in the car. She strikes the air bag, bringing her body to a stop in 0.56 s. What average force does the air bag exert on her
Physics
2 answers:
andre [41]3 years ago
6 0

Answer:

F = 3,445.71 N

Explanation:

Finding the deceleration (a):

a = \frac{u - v}{t}

initial velocity = u = 40.2 m/s

final velocity = v = 0 m/s

a = 40.2/0.56 = 71.785 m/s^2

Now, Finding the force:

F = ma

mass = m = 48.0 kg

a = 71.785 m/s^2

the force is found to be 3,445.71 N

Bogdan [553]3 years ago
3 0

Answer:

F = 3445.714\,N

Explanation:

The system can be modelled appropriately by the use of the Principle of Momentum Conservation and Impact Theorem:

(48\,kg)\cdot (40.2\,\frac{m}{s} ) - F\cdot (0.56\,s) = 0\,\frac{kg\cdot m}{s}

The average force exerted on her:

F = 3445.714\,N

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The dilation of time.

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Explanation:

I have explained in the image attached below.

From the explanation, the correct ones are;

The dilation of time.

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What is the significance of the nose end marking on a rocket or missile?
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How are acceleration and speed related​
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Explanation:

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Explain what is the capacity of a battery in your own words​
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4 0
3 years ago
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car ent
Paha777 [63]

Answer:

0.8712 m/s²

Explanation:

We are given;

Velocity of first car; v1 = 33 m/s

Distance; d = 2.5 km = 2500 m

Acceleration of first car; a1 = 0 m/s² (constant acceleration)

Velocity of second car; v2 = 0 m/s (since the second car starts from rest)

From Newton's equation of motion, we know that;

d = ut + ½at²

Thus,for first car, we have;

d = v1•t + ½(a1)t²

Plugging in the relevant values, we have;

d = 33t + 0

d = 33t

For second car, we have;

d = v2•t + ½(a2)•t²

Plugging in the relevant values, we have;

d = 0 + ½(a2)t²

d = ½(a2)t²

Since they meet at the next exit, then;

33t = ½(a2)t²

simplifying to get;

33 = ½(a2)t

Now, we also know that;

t = distance/speed = d/v1 = 2500/33

Thus;

33 = ½ × (a2) × (2500/33)

Rearranging, we have;

a2 = (33 × 33 × 2)/2500

a2 = 0.8712 m/s²

3 0
3 years ago
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