Brainliest! please help <3
1 answer:
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Answer:
a. No, since the value of the test statistic is less than the critical value
Step-by-step explanation:
1) Data given and notation
n=144 represent the random sample taken
X=72 represent the number of people that prefer the blend
estimated proportion of people that prefer the blend
is the value that we want to test
represent the significance level
Confidence=99% or 0.959
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
2) Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the true proportion if higher than 0.47:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
3) Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
4) Statistical decision
We can calculate the critical value since we have a right tailed test, we need to look into the normal standard distribution a value that accumulates 0.01 of the area on the right and 0.99 on the left. And this value is:
And we can use the following excel code to find the critical value: "=NORM.INV(0.99,0,1)"
Our calculated value on this case is less than the critical value so the best conclusion is:
a. No, since the value of the test statistic is less than the critical value