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Alinara [238K]
4 years ago
7

Which of these are components of DNA? Check all that apply.

Chemistry
1 answer:
Kipish [7]4 years ago
6 0

Answer:

  1. deoxyribose sugar molecules.
  2. adenine.
  3. cytosine.
  4. thymine.
  5. phosphate molecules.

Explanation:

Hope it helps.

You might be interested in
Be sure to answer all parts.
MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol

Now, molarity of ethanol solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol

Now, molarity of sucrose solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L}  (1 mL = 0.001 L)\\= 0.94 M

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol

Now, molarity of sodium chloride solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0
3 years ago
Please help with word equations?
Delvig [45]
For the answer to the questions above, 

a) Ag2CO3(s) => Ag2O(s)+CO2(g) 

<span>b) Cl2(g)+2(KI)(aq) => I2(s)+2(KCl)(aq) (coefficients are for balanced equation) </span>
<span>net ionic is Cl2(g)+2I- => I2(s)+2Cl-(aq) </span>

<span>c) I2(s)+3(Cl2)(g)=>2(ICl3)
</span>I hope I helped you with your problem
7 0
4 years ago
assuming that each human being has 60 trillion body cells in that the earths population is 6 billion calculate the total number
sesenic [268]

3.6 x 10²³

Explanation:

Given parameters:

  Number of cell per body = 60 trillion body cells

   Population of the earth = 6 billion

Unknown:

Total number of living human body cells = ?

Solution:

  To solve this problem, simply find the product:

 Total number of living human body cells = number of cell per body x population of the earth

          1 trillion = 1 x 10¹²

         60 trillion = 6 x 10¹³

         1 billion = 1 x 10⁹

         6 billion = 6 x 10⁹

Total number of living human body cells = 6 x 10¹³ x  6 x 10⁹

                                                                      = 6 x 6 x 10⁽¹³⁺⁹⁾

                                                                       = 36 x 10²² or 3.6 x 10²³

learn more:

Product brainly.com/question/10541435

#learnwithBrainly

7 0
4 years ago
The electron configuration 1s2 is correct for an element that has 2 electrons, both in the first principle energy level
Molodets [167]

Answer:

The answer is True

Explanation:

I got it right on my quiz, hope this helps!

5 0
3 years ago
Dog a is given one cup of food. Dog b is given 1/2 cup of food . Dog.c is given two cups of food at the end of the year dog c we
dusya [7]

Dependent variable: Weight

Independent variable: Amount of food

Explanation:

In experiments such as the one described, there are two or more factors involved, which act as variables. Additionally, these factors can be classified as dependent or independent. The difference between these two is that the independent factor is changed on purpose by the researcher. This occurs with the amount of food as each dog receives a different amount of food and this is controlled by the researcher.

On the other hand, the dependent variable is the main factor analyzed in the experiment or the factor that is modified by the independent variable. In the experiment presented, the dependent variable is weight because in this experiment the focus is to analyze how weight changes with different amounts of food, and this factor is affected by the independent variable.

8 0
3 years ago
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