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3 years ago

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3. Skunks run about 10 miles per hour and won't try to outrun a predator. Instead, they

1 answer:

Andrej [43]3 years ago

4 0

Answer:

heelpindgbsjdjfjfhjf d drrr¾rereerrrr. freee points

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Soils that allow water to pass through them faster are more _______.

siniylev [52]

I would say C. Permable

Google def.(of a material or membrane) allowing liquids or gases to pass through it.
"a frog's skin is permeable to water

Porous- (of a rock or other material) having minute spaces or holes through which liquid or air may pass

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3 years ago

Read 2 more answers

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?

Margaret [11]

Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

Explanation:

The formula for molality is:

$m=\frac{moles \ of \ solute}{kg \ of \ solvent}$

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

$moles= 0.210 \ mol \\kilograms = 0.075 \ kg$

Substitute the values into the formula.

$m= \frac{ 0.210 \ mol }{0.075 \ kg}$

Divide.

$m= 2.8 \ mol/kg= 2.8 \ m$

The molality is <u>2.8 moles per kilogram</u>

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3 years ago

Lenses are made to have different focal points. What two properties of a lens

Novay_Z [31]

The correct answer is letter C

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3 years ago

Draw what a chromosome looks like during metaphase. identify the chromatids and the centromere

netineya [11]

This is what a chromosome looks like during mataphase

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3 years ago

6) A volume of 473 mL of oxygen was collected at 27°C. What volume would the oxygen occupy at

sertanlavr [38]

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K$

Now put all the given values in above equation, we get:

$\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL$

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

6 0

3 years ago