Answer:
Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below
The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.
Explanation:
The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.
In the Left Beaker (Left half cell), their is less concentration
Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side
In the Right Beaker (right half cell), their is more concentration
Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side
Electrons will flow from Left to Right direction.
Answer:
Explanation:
to convert any value in miles per second to meters per second, just multiply the value in miles per second by the conversion factor 1609.344. So, 10095 miles per second times 1609.344 is equal to 1.625 × 107 meters per second.
About 6.5x10^22 molecules.
(5g C2H5OH)x(1 mol C2H5OH/46g C2H5OH)x(6.02x10^23 molecules C2H5OH/1 mol C2H5OH)=(3.01E24)/46=6.5x10^22.
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Answer:
Explanation:
half life = 1600 years .
m = M x 
m is mass of the radioactive object after n half lives , M is original mass.
n = 4800 / 1600
= 4
Putting the valus of n and M we have
m = .25 x 
= .03125 g .
Phosphates and deoxyribose