Please help with word equations?

1 answer:

7 0

For the answer to the questions above,

a) Ag2CO3(s) => Ag2O(s)+CO2(g)

b) Cl2(g)+2(KI)(aq) => I2(s)+2(KCl)(aq) (coefficients are for balanced equation) 
net ionic is Cl2(g)+2I- => I2(s)+2Cl-(aq) 

c) I2(s)+3(Cl2)(g)=>2(ICl3)
I hope I helped you with your problem

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What is the atomic nucleus made of ?

oksian1 [2.3K]

Answer: nucleons

Explanation:

The nucleons are the particles that constitue the nuclei of the atoms. Those are protons and neutrons.

They are not elementary particles (quarks are the elementary particles that form both protons and neutrons).

Protons are the particles that define the elements. Any different elements have different number of protons. H has one proton, He has 2 protons, Li has three protons, Na has 11 protons, U has 92 protons.

Protons are positively charged and the number of protons in any neutral atom is equal to the number of electrons (the electrons, which are elementary negatively charged particles, are around the nucleous).

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3 years ago

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Charlotte is driving at 58.6 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 4

kramer

Answer: 19.71 feet

Explanation:

Given: Speed of Charlotte =58.6 mi/h

Since 1 hour = 3600 seconds

and 1 mile = 5280 feet

So, Speed of Charlotte = $\dfrac{58.6\times5280}{3600}\approx85.95$ mi/ sec

She looks down at her phone and takes her eyes off the road for 4.36 s.

Since , Distance = $\dfrac{speed}{time}$

So, Distance = $\dfrac{85.95}{4.36}=19.71\ feet$

Hence, Charlotte traveled 19.71 feet during this time.

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2 years ago

Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de

nignag [31]

Answer:

$\%m/m=14\%$

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

$[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}$