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irinina [24]
4 years ago
8

Please help with word equations?

Chemistry
1 answer:
Delvig [45]4 years ago
7 0
For the answer to the questions above, 

a) Ag2CO3(s) => Ag2O(s)+CO2(g) 

<span>b) Cl2(g)+2(KI)(aq) => I2(s)+2(KCl)(aq) (coefficients are for balanced equation) </span>
<span>net ionic is Cl2(g)+2I- => I2(s)+2Cl-(aq) </span>

<span>c) I2(s)+3(Cl2)(g)=>2(ICl3)
</span>I hope I helped you with your problem
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Number the elements sodium, magnesium, phosphorus, and chlorine in the predicted order ionization energies from the highest to t
storchak [24]

Answer:

It goes 4 3 2 1

Explanation:

Alphabetical order

6 0
3 years ago
Read 2 more answers
Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of
Vlad1618 [11]

Answer:

0.745 and 0.245

Explanation:

Mole fraction (χ) is  the number of moles of a component divided by the total number of moles in a mixture.  

We must calculate the moles of each component.  

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

\text{n} _{1} = \text{8.65 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _{2} = \text{4.32 g} \times \dfrac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}

2. Calculate the total moles.

n_{\text{tot}} = \text{n}_{1} + \text{n}_{2} = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}

3. Calculate the mole fraction of each component

\chi_{1} =\dfrac{0.1965}{0.2640} = \mathbf{0.745}\\\\\chi_{2} =\dfrac{0.06744}{0.2640} = \mathbf{0.255}

6 0
3 years ago
Here is a picture and diagram of the question
Aleks [24]
Maybe not all of it because the heat would go back in forth in the aluminum bar and some of it will be given and some may even be lost because heat is just atoms moving faster and eventually those atoms will slow down
3 0
3 years ago
When an ice cube melts it is still water
Leto [7]

Answer:

yes it is still water

Explanation:

4 0
3 years ago
Read 2 more answers
Un convertidor catalítico acelera la reacción del monóxido de carbono con oxígeno para producir dióxido de carbono. ¿De qué mane
vaieri [72.5K]

Answer:

a. Disminuye.

b. Disminuye.

Explanation:

¡Hola!

En este caso, considerando que tenemos una reacción en la cual se podría asumir que tanto la concentración de monóxido de carbono y la de oxígeno contribuye a la velocidad de reacción, de acuerdo a la siguiente cinética elemental:

r=k[CO]^2[O_2]

Al aplicar los siguientes cambios, resultaría:

a. En este caso, bien sabemos que la velocidad de reacción es aumentada al adicionar un catalizador ya que la constante de velocidad aumenta al disminuir la energía de activación; no obstante, al retirar el catalizador, la energía de activación aumentaría y por consiguiente la velocidad de reacción disminuiría.

b. En este caso, dado que la relación entre el oxígeno y la rapidez de reacción es directamente proporcional, es possible para nosotros determinar que al eliminar parte del oxígeno, la concentración disminuye y por ende la velocidad de reacción también.

¡Saludos!

5 0
3 years ago
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