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2 years ago

Evaluate g(x) = 2x - 7 over the domain (2, 4, 6, 8) what is the range of g(x)

Mathematics

1 answer:

Elanso [62]2 years ago

8 0

Answer:

-3, 1, 5, 9

Step-by-step explanation:

2(2) - 7 = -3

2(4) - 7 = 1

2(6) - 7 = 5

2(8) - 7 = 9

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Law of reflection. Easy question please help (picture included)

PIT_PIT [208]

Simple. The Law of Reflection states that the angle of incidence is equal to the angle of reflection. These two angles are measured relative the normal line (line perpendicular to the surface). The angle of reflection is therefore 34 degrees also. However, since the question is asking for the angle relative to the mirror, then the answer is 90-54 = 36° Thus your answer is C. 36°

6 0

3 years ago

A car went 64 miles on 2 gallons of gas in the morning, 16 miles on 1/2 gallon of gas at noon, and 32 miles on 1 gallon of gas a

Marina86 [1]

Answer:

Yes,

Step-by-step explanation:

You take 64 miles for 2 gallons and divide it by 2. And it leads up to 32 miles and 1 gallon. Now you divide that by 2 again and get 16 miles and 1/2 gallon. So, to check that you can take 16+16 and you get 32 and take 32+32 and you get 64.

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2 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0

2 years ago

(0, -9) and (-3, -3) I need this problem solved with work please!

nirvana33 [79]

Answer:

-9-(-3)/0-(-3) = -3/3 = -1

y+9= -1(x-0) Point Slope form

y+9-9= -1x-9

y= -x-9 Slope Intercept form

y+x+9 = -x-9 +x+9

y+x+9= 0 General form

4 0

3 years ago