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zhenek [66]
3 years ago
7

- How many moles of S2 are needed to produce 1.50 moles of SO2 gas? S2 + 20, ----> 2802​

Chemistry
1 answer:
matrenka [14]3 years ago
3 0

Answer:

0.75 moles

Explanation:

S2 + 2O2 = 2SO2

From the reaction above,

We see that number of moles attached to S2 is 1 and number of moles attached to SO2 is 2.

Since we want to find how many moles of S2 are needed to produce 1.50 moles of SO2 gas

The answer is gotten by proportion;

Number of moles = 1/2 × 1.5 = 0.75 moles

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From these, we must devise the target equation:  

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The target equation has 2NH₃ on the left, so you <em>reverse equation (I)</em>.  

When you reverse an equation, you <em>reverse the sign of its ΔH</em>.  

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Equation (V) has 1N₂ on the right, and that is not in the target equation.  

You need an equation with 1N₂ on the left.  

<em>Reverse Equation (III).</em>  

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Equation <em>(VI)</em> has ³/₂O₂ on the right, and that is not in the target equation.  

You need ³/₂O₂ on the left.  

Multiply <em>Equation (II) by three</em>.  

When you multiply an equation by three, you <em>multiply its ΔH by thre</em>e.

(VII) 3H₂ +³/₂O₂ → 3H₂O; Δ<em>H</em> = -286 kJ  

Now, you add equations (V), (VI), and (VII), <em>cancelling species</em> that appear on opposite sides of the reaction arrows.  

When you add equations, you add their Δ<em>H</em> values.  

_______________________________________

We get the target equation (IV):  

(V) 2NH₃ → <u>N</u>₂ + <u>3H</u>₂;                                    ΔH = +  92 kJ  

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(VII) <u>3H</u>₂ +³/₂<u>O</u>₂ → <u>3</u>H₂O;                             ΔH =   -286 kJ

(IV) 2NH₃ + CO₂ → CO(NH₂)₂ + H₂O;          ΔH =  +438 kJ  


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