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zhenek [66]
3 years ago
7

- How many moles of S2 are needed to produce 1.50 moles of SO2 gas? S2 + 20, ----> 2802​

Chemistry
1 answer:
matrenka [14]3 years ago
3 0

Answer:

0.75 moles

Explanation:

S2 + 2O2 = 2SO2

From the reaction above,

We see that number of moles attached to S2 is 1 and number of moles attached to SO2 is 2.

Since we want to find how many moles of S2 are needed to produce 1.50 moles of SO2 gas

The answer is gotten by proportion;

Number of moles = 1/2 × 1.5 = 0.75 moles

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How to balance the chemical equation: <br> CO2+H2O--&gt;C6H12O6
Andru [333]

Answer:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

Explanation:

The given reaction represent the formation of glucose so it is photosynthesis reaction.

Photosynthesis:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Carbon dioxide + water + energy →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture  by chloroplast.

Chemical equation:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

it is known from balanced chemical equation that 6 moles of carbon dioxide react with the six moles of water and created one mole of glucose and six mole of oxygen.

4 0
3 years ago
In order to dry wet clothes, we spread them on a clothline. This is because (i) spreading increases surface area (ii) clothes be
Novosadov [1.4K]

Answer:

this is because spreading it makes more sunlight hit the cloth which results in it drying faster

3 0
3 years ago
What is the valency of element sulphur ​
NISA [10]
I am not to sure because I have not studied this
3 0
3 years ago
Read 2 more answers
How many mL of a stock 50% (w/v) KNO3 solution are needed to prepare 250 mL of a 20% (w/v) KNO3 solution?
Andre45 [30]

Answer:

100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.

Explanation:

In the given question it is mentioned that

     S1=50%

      V2=250ml

      S2= 20%

We all know that

                     V1S1=V2S2

                     ∴V1=  V2×S2÷S1

                     ∴V1=  V2S2×1/S1

                      ∴V1= 250×20÷50

                       ∴V1= 100ml

 

6 0
3 years ago
A saturated solution of baso4 has a concentration of 0.5mol/l. a 55ml sample is taken by you. what is the mass of baso4 in the s
SIZIF [17.4K]

Answer:

6.4 g BaSO₄

Explanation:

You have been given the molarity and the volume of the solution. To find the mass of the solution, you need to (1) find the moles BaSO₄ (via the molarity ratio) and then (2) convert moles BaSO₄ to grams BaSO₄ (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given values.

Molarity (mol/L) = moles / volume (L)

(Step 1)

55 mL / 1,000 = 0.055 L

Molarity = moles / volume                             <----- Molarity ratio

0.5 (mol/L) = moles / 0.055 L                        <----- Insert values

0.0275 = moles                                             <----- Multiply both sides by 0.055

(Step 2)

Molar Mass (BaSO₄): 137.33 g/mol + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (BaSO₄): 233.387 g/mol

0.0275 moles BaSO₄          233.387 g
---------------------------------  x  -------------------  =  6.4 g BaSO₄
                                                1 mole

6 0
2 years ago
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