Answer:
A)100mL B)50mL C)The second option D)Hypoosmotic Environment
Explanation:
The average Na concentration in the seas and oceans of the world is around 3,5% which mean that in 100 ml of sea water, there is around 3,5 grams of Na.
The weight of one mol of NaCl is 58,44 grams. For 3,5 grams of NaCl, we get 3,5/58,44 = 0,060 mol of NaCl which is 0,060x1000 = 60 mmol/100ml. According to this and the information given in the question about the secretion of the salt glands', if the average sodium concentration is 600mmol/L, we have 60*10 = 600mmol/L so it would take 100 mililiters of water to excrete.
If the average Na concentration of the salt gland's secretion were 300 mmol/L, only 50 mililiters of water would be needed to excrete the same sodium load.
The second option of secretion is hyperosmotic to seawater because the concentration is higher.
Osmoregulation is the process of balancing the amount of water and salt between the body of the organism and its surrounding environment. For salt glands to be advantageous for osmoregulation, they need to be in a hypoosmotic environment.
I hope this answer helps.
Answer:
Option B. is correct
Explanation:
Vegetarianism is the practice of abstaining from by-products of animal slaughter and the consumption of meat. Vegetarianism is often cited as a partial solution to the growing problem of deforestation and other types of habitat destruction as the human population continues to grow. The reason for this is more people can be fed using less agricultural land because vegetarians eat at a lower trophic level.
Option B. is correct
Answer:
When a mustard plant seedling is transferred to an environment with higher levels of carbon dioxide, the new leaves have a lower stomata-to-surface-area ratio, it is because the concentration of carbondioxide is high in the surrounding so the plant produce small leaves having less number of stomata. If the concentration of carbondioxide is lower so big leaves are produced having maximum number of stomata.
