SOLUTION:
To begin with, let's establish that the formula of this line is in slope-intercept form as follows:
y = mx
The formula for this line isn't:
y = mx + b
This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:
y = mx + b
y = mx + 0
y = mx
Moving on, for ( m ), we need to find the gradient of the line as displayed below:
m = gradient
m = rise / run
m = 10 / 2
m = 5
Now, we must simply substitue ( m ) into the formula in order to obtain the equation for this line as displayed below:
y = mx
y = 5x
Therefore, the answer is:
A. y = 5x
V(x) = (2x - 3)/(5x + 4)
The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.
{x | x ∈ R, x ≠ -4/5}
w(x) = (5x + 4)/(2x - 3)
similarly, x ≠ 3/2
so, {x| x ∈ R, x ≠ 3/2}
Answer: The slope is 15/4.
Step-by-step explanation:
M = (y2 - y1)/(x2 - x1)
M = (5 - (-10))/(-1 - (-5))
M = (5 + 10)/(-1 + 5)
M = 15/4
I think the answer is d. The slope of AC=Slope of DF.
Hope this helped☺☺
Answer:
The first set is a set of linear equations.
The way to figure this out is pretty easy. If you want to see it visually, go search up desmos graphing calculator and put in these equations.
A linear equation is a function that has a constant slope, meaning that the rate it increases or decreases will never change. The first one is a set of linear equations because it is 2 equations with constant slopes, meaning that the slopes will never change no matter what y and x are.
The second set is not, because while the first equation is linear, the second is an inequality. While it is a straight line, it doesn't count as a linear equation.
The third set, both equations have exponents on the x, which means that the slope will change depending on x. This means that both of these are not linear equations.
The only set that is a linear set is the one that has only linear equations.
