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Vanyuwa [196]
3 years ago
7

1. Let f(x) = 2x^+x-3 and g(x) = x-1 preform the indicated operation, then find the domain.

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

Step-by-step explanation:

#1

  • f(x) = 2x^2 + x - 3
  • g(x) = x - 1

<u />\text{Find (f - g)(x):}

  • (f - g)(x) = f(x) - g(x) = 2x^2 + x - 3 - x + 1 = 2x^2 - 2

Correct choice is D

  • <em />\text{The rest of the parts are confusing since f(x) and g(x) are same as in the first part}
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Alenkasestr [34]
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To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
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So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)

And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
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1 gets us -5 
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2 years ago
(4x - 3) × (x + 2)=0
matrenka [14]

Hi,

AxB = 0 means A=0. or B=0

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