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2 years ago

. hengityksen säätely

Biology

2 answers:

vladimir1956 [14]2 years ago

7 0

Sorry I don’t really understand .....

densk [106]2 years ago

6 0

Answer:

Hengityksen hallinta tarkoittaa hellävaraista hengittämistä, vähäisimmällä vaivalla. Se auttaa, kun sinulla on hengähdystauko tai tunnet ahdistusta. Alla olevaa tekniikkaa opetetaan joskus joogassa. Tottuaksesi hengityksen hallintaan, se auttaa harjoittelemaan istuessasi, rentona eikä hengästyneenä.

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Many species of gulls feed their chicks by regurgitating food. When parents return from foraging, the gull chicks peck at a red

makvit [3.9K]

Answer:

fixed action pattern, key stimulus; key stimulus, fixed action pattern

Explanation:

An innate behavior which specific to a species and is highly stereotyped is termed as a fixed action pattern.
This behavior occurs due to a neuronal network that is hard-wired in the species and the response is said to be generated following a key stimulus.
A key stimulus is the one that generates a fixed action pattern and this is also called a releaser.
A key stimulus can be in the form of shape, sound, color, or a combination of these.
In this case, the red spot is a stimulus for the chicks which causes them to peck at their parent's bill, and hence, the red spot is a key stimulus, and pecking of the chicks is a fixed action pattern.
The parents regurgitate the food only when the chicks peck at their bills, so pecking is a key stimulus for the parents which causes them to regurgitate the food which is a fixed action pattern.

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2 years ago

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snow_lady [41]

Answer:

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Explanation:

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In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2

Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

$r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

$r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75$

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

$r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha$

So, on average, each year the number of pines per hectare increases by 0.3

7 0

2 years ago