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GalinKa [24]
3 years ago
5

. hengityksen säätely

Biology
2 answers:
vladimir1956 [14]3 years ago
7 0
Sorry I don’t really understand .....
densk [106]3 years ago
6 0

Answer:

Hengityksen hallinta tarkoittaa hellävaraista hengittämistä, vähäisimmällä vaivalla. Se auttaa, kun sinulla on hengähdystauko tai tunnet ahdistusta. Alla olevaa tekniikkaa opetetaan joskus joogassa. Tottuaksesi hengityksen hallintaan, se auttaa harjoittelemaan istuessasi, rentona eikä hengästyneenä.

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Studying the folding patterns of protein molecules can help microbiologists better understand cellular processes as well as some
xz_007 [3.2K]
The best answer in this case is C, "the researchers applied creativity to solve a problem in running an experiment".

Distributing the computing load across the global community by sharing processing power is a creative response to tackle the challenge in simulating protein folding for the experiment. This does not change or reduce the scientific merits of the experiment, so we can discount the first two answers (a & b). Answer d talks about well established scientific techniques, although the question wasn't really centered around the specific techniques, so it's not as relevant an answer as C.
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4 years ago
A couple without an ancestral history of Tay-Sachs disease (a rare autosomal recessive) have two normal children and an infant a
Bas_tet [7]

Answer:

The probability is 25%.

Explanation:

  • Let the dominant allele for the disease be 'T' and recessive allele be 't'.
  • The couple with normal phenotype produces an infant with the Tay Sach's disease.
  • As the disease is autosomal recessive in nature, it will get expressed in a homozygous recessive condition, that is, when the genotype is : tt.
  • As the normal parents are producing a diseased offspring, the both parents must be heterozygous dominant (Tt) for the disease allele.
  • The brother of the husband and the sister of the wife, both having a normal phenotype, can have the following genotypes, TT or Tt.
  • If either of the individual (brother or sister) has TT genotype and the other has other has either TT or Tt genotype, there is zero probability that they will produce an offspring with the disease.

                     T          T                        and                       T            T

             T     TT        TT                                             T     TT         TT

                     (N)        (N)                                                    (N)        (N)

             T      TT        TT                                             t      Tt          Tt        

                     (N)        (N)                                                    (N)         (N)

  • If both the individuals have a Tt genotype, the probability to produce  diseased offspring is one-fourth or 25%.

                                               T             t

                                   T        TT           Tt

                                             (N)           (N)

                                    t        Tt             tt

                                             (N)           (D)

  • (N) stands for normal and (D) stands for diseased phenotype.

           

7 0
4 years ago
HELP MEH PIZZAZZ. I WILL GIVE 20 points .
andreev551 [17]

The anwser is number 2 I think,



Hope it helps!

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Explanation:

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