1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena-s [515]
3 years ago
12

An atom has 10 protons and 10 electrons. What happens to the charge if you add 1 more electron

Chemistry
1 answer:
Fed [463]3 years ago
8 0

Answer:

it becomes a negstive charge

You might be interested in
What does the root “thermal” mean?<br> Please Help<br> I will give you Brainliest
Nezavi [6.7K]

Answer:

If it has to do with heat, it's thermal. ... The Greek word therme, meaning “heat,” is the origin of the adjective thermal. Something that is thermal is hot, retains heat, or has a warming effect.

Explanation:

hope it helps :)

7 0
3 years ago
What is the total distance covered if you walk 5 meters to the north 5 meter east 5 meters south
mihalych1998 [28]

0! because you walked back in forth in diferent direcions

8 0
3 years ago
How many H2O molecules are in 183.2 grams of H20 gas?
jek_recluse [69]

Answer: There are 61.24 \times 10^{23} molecules present in 183.2 grams of H_{2}O gas.

Explanation:

Given: Mass = 183.2 g

Number of moles is the mass of substance divided by its molar mass.

As molar mass of water is 18 g/mol. Therefore, moles of H_{2}O are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{183.2 g}{18 g/mol}\\= 10.17 mol

According to the mole concept, there are 6.022 \times 10^{22} molecules present in one mole of a substance.

Hence, molecules present in 10.17 moles are calculated as follows.

10.17 mol \times 6.022 \times 10^{23}\\= 61.24 \times 10^{23}

Thus, we can conclude that there are 61.24 \times 10^{23} molecules present in 183.2 grams of H_{2}O gas.

6 0
3 years ago
Select all that apply.
kap26 [50]
I think it is A and C!
3 0
2 years ago
A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mm Hg. The flask is opened and more gas is added to the flask. The new
Artyom0805 [142]

Answer: There are now 2.07 moles of gas in the flask.

Explanation:

PV=nRT

P= Pressure of the gas = 697 mmHg = 0.92 atm  (760 mmHg= 1 atm)

V= Volume of gas = volume of container = ?

n = number of moles = 1.9

T = Temperature of the gas = 21°C=(21+273)K= 294 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

V=\frac{nRT}{P}=\frac{1.9\times 0.0821 \times 294}{0.92}=49.8L

When more gas is added to the flask. The new pressure is 775 mm Hg and the temperature is now 26 °C, but the volume remains same.Thus again using ideal gas equation to find number of moles.

PV=nRT

P= Pressure of the gas = 775 mmHg = 1.02 atm  (760 mmHg= 1 atm)

V= Volume of gas = volume of container = 49.8 L

n = number of moles = ?

T = Temperature of the gas = 26°C=(26+273)K= 299 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

n=\frac{PV}{RT}=\frac{1.02\times 49.8}{0.0821\times 299}=2.07moles

Thus the now the container contains 2.07 moles.

6 0
3 years ago
Other questions:
  • How many grams of nitroglycerin are needed to produce 25.0 grams of CO2
    11·1 answer
  • C. Write a complete ionic equation for the reaction and identify the spectator ions.
    10·1 answer
  • Which example best represents the use of creativity in scientific inquiry?
    7·2 answers
  • A base is a substance that accepts protons. true or false?
    8·2 answers
  • How do you calculate bonding capacity in chemistry?
    8·1 answer
  • Which is not one of the parts of the cell theory.
    12·1 answer
  • A compound is 40.0 % C, 53.3 % 0, and 6.66 % H What is its molecular formula if its molecular mass is 60 g? Show all your work
    13·1 answer
  • Ughh please help me ​
    8·2 answers
  • En 200 gramos de carburo de potasio ,cuya fórmula química es K4C , Cuántos moles de esa sustancia existen ?
    9·1 answer
  • The graph below shows how solubility changes with temperature.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!