1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kifflom [539]
2 years ago
10

6. What is the molarity of 175 mL of solution containing 2.18 grams of NazS04-10H2O?​

Chemistry
1 answer:
Ymorist [56]2 years ago
8 0

Answer:

Molarity\,\,of\,\,the\,\,solution\,\,is\,\,S=0.039M

Explanation:

W=2.18 g\\M=322g\\V=175mL=0.175L\\\\S=\frac{W}{MV} \\=>S=\frac{2.18}{322*0.175} \\So,S=0.039M

Hope you have understood this.....            

ask me if you have any confusion.....          

if you liked it pls mark it as the brainliest

You might be interested in
What is the mole ratio of the following equation?
Liono4ka [1.6K]
The mole ratio would be 2:2:2
7 0
2 years ago
Which of the following causes a physical change in the shape of an object?
babunello [35]

Answer:

B

Explanation:

Heating a piece of iron until it glows.

3 0
2 years ago
Two copper pennies has a mass of 6.64g how many moles of copper do they contain<br>​
Ann [662]

Answer:

It contains 0.105 mole cu

Explanation:

3 0
3 years ago
Molar mass of Ag2SO4<br><br> Full work Pls
IceJOKER [234]
This would be the molar mass.

5 0
3 years ago
One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO
zhenek [66]
Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
 2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s)  and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
                                                                                     = 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
                                                         = 1000 x 10³ g / 226 g mol⁻¹
                                                         = 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x \frac{3}{2}
                                                     = 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
                                        = 703540.02 g
                                        = 703.540 kg

Hence, the theoretical yield of Na₂CO₃ =  703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
                            = 92.34%
7 0
3 years ago
Other questions:
  • URGENT! Will give 20 points.
    15·2 answers
  • ) determine the theoretical yield and the percent yield if 21.8 g of k2co3 is produced from reacting 27.9 g ko2 with 29.0 l of c
    14·2 answers
  • WHAT DID YOU OBSERVE HAPPENED WHEN AN S-WAVE TRAVELED INTO A LIQUID?
    9·1 answer
  • How many liters of a 3.67 M K2SO4 solution are needed to provide 57.3 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equi
    15·1 answer
  • This system relates to the process by which an organism gets rid of its waste.
    10·2 answers
  • Which of the following correctly shows the relationship, in terms of number of particles, of the three substances?
    11·1 answer
  • What is the reduction half-reaction for 2Mg + O2 → 2Mgo?
    13·1 answer
  • 이
    8·1 answer
  • An oxide of P contains 50% by mass of P. Its Relative molecular mass is 64. The molecular formula of the oxide is (P=32; O=16)
    6·1 answer
  • the solubility of nitrogen gas is 1.90 mL/dL of blood at 1.00 atm. what is the solubility of nitrogen gas in a deepsea divers bl
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!