Question

6. What is the molarity of 175 mL of solution containing 2.18 grams of NazS04-10H2O?​

Answer 1

Answer:

$Molarity\,\,of\,\,the\,\,solution\,\,is\,\,S=0.039M$

Explanation:

$W=2.18 g\\M=322g\\V=175mL=0.175L\\\\S=\frac{W}{MV} \\=>S=\frac{2.18}{322*0.175} \\So,S=0.039M$

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