Question

A circular loop of wire with a radius of 12.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.8 T is directed along the positive z-direction, which is upward.
If the loop is removed from the field region in a time interval of 2.8 ms, find the average emf that will be induced in the wire loop during the extraction process.

Answer 1

Answer:

The average induced emf is 29.06 V

Explanation:

Given;

radius of the circular loop, r = 12.0 cm = 0.12 m

magnetic field strength, B =  1.8 T

time interval = 2.8 ms = 0.0028 s

Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

$e.m.f =\frac{BA}{t}$

where;

B is magnetic field

A is area

t is time

substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

$e.m.f =\frac{1.8 *0.0452}{0.0028} = 29.06 \ V$

Therefore, the average induced emf is 29.06 V