Ask question

Ask question

All categories

2 years ago

12

8. How do you think that might be the reason why the Sun warms more in the summer? To give your explanation can rely on the angl

e of the sunlight falling in the months: January, March and June.

1 answer:

gregori [183]2 years ago

8 0

Answer:

Because the angle of the sun moves/rotates in the summer, the sun's rays move their angle and impact the earth.

You might be interested in

The sun's energy is stored in fossil fuels. true or false.

Scilla [17]

Yes,suns original energy are still stored at the bonds of fossils in which they taken long,long time ago and these fossils powered now industries,fuel for vehicles.In those chemical bonds holds much energy packed together for centuries.

8 0

3 years ago

Don’t need to answer a question just say something and you’ll get Marked brainliest (Free points WONT GET BRAINLIEST RIGHT AWAY)

stiks02 [169]

Answer:

a

Explanation:

7 0

3 years ago

Read 2 more answers

The strongest known magnetic field is that of _____.

NeTakaya

A magnetar. It is a neutron star that has an amazing strong magnetic field.

I hope this helps!

8 0

3 years ago

As keisha runs the generator, which best describes what should happen to the needle that measures electric current? it will move

SOVA2 [1]

The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.

What is an electric generator?

An electric generator is physically equivalent to an electric motor. but it converts mechanical energy into electrical energy.
The electrical field generated is dependent on the inclination of the wire with respect to magnetic field lines, and this inclination changes over time,

because of that she will experience a varying electrical field, and thus a varying electric current will be zero.

The maximum positive value will occur when the wire is perpendicular to the magnetic field lines after one-fourth of rotation, and then zero.

Hence option C is correct.

The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.

Learn more about electric generator here:

<u>brainly.com/question/12296668</u>

<u />

#SPJ4

6 0

2 years ago

What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.

valkas [14]

<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period $T$ of a body (moon, planet, satellite) orbiting a greater body in space with the size $a$ of its orbit.

This Law is originally expressed as follows:

$T^{2}=\frac{4\pi^{2}}{GM}a^{3}$ (1)

Where;

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M=6.39(10)^{23}kg$ is the mass of Mars

$a=3.4(10)^{6}m$ is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

$T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}$ (2)

$T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}$ (3)

$T=\sqrt{11581157.44 s^{2}}$ (4)

Finally:

$T=3403.1099s=56.718min$ This is the orbital period of a spacecraft in a low orbit near the surface of mars

6 0

3 years ago