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zlopas [31]
3 years ago
7

Hi can you please help me ​

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Answer:

<h2>y = 29</h2><h2>x = 31</h2><h2 />

Step-by-step explanation:

opposite angle 3y = 87

                           y = 87/3

                          y = 29

solve for x:

3x = 180 - 87

x = 93 / 3

x = 31

added image

Licemer1 [7]3 years ago
3 0
For this you need to know your angles in parallel lines.
3y will equal 87 as they are opposite angles and opposite angles are equal.
So y = 87/3
We can use the knowledge that angles in a straight line (in parallel line diagrams) will add up to 180. Therefore we do 180-87= 93. Now we know 3x=93 because just like the first example they are opposite angles. Now we know x=93/3.
(I didn’t have a calculator on me so you’ll have to work out the final result. Also I recommend looking into angles in parallel lines. I tried my best to explain so I hope you understand the jist of what I was trying to say.)
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Step-by-step explanation:

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3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
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<h2>Answer:</h2>

\frac{2}{x}

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<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

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iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

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c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

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Step-by-step explanation:

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