You buy 3 pairs of jeans for $35.95 each and get a fourth pair for free. What is your cost per pair of jeans?

How many pounds is equivalent to 168 ounces

riadik2000 [5.3K]

10.5 pounds is the answer to the question

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3 years ago

The Russet Potato Company has been working on the development of a new potato seed that is hoped to be an improvement over the e

Elodia [21]

Answer:

$F=\frac{s^2_2}{s^2_1}=\frac{0.8^2}{1.0^2}=0.64$

$p_v =P(F_{15,10}$

Since the $p_v > \alpha$ we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation for the New sample it's significantly less than the variation for the Old sample at 5% of significance.

Step-by-step explanation:

Data given and notation

$n_1 = 11$ represent the sampe size for the Old

$n_2 =16$ represent the sample size for the New

$\bar X_1 =6.25$ represent the sample mean for Old

$\bar X_2 =5.95$ represent the sample mean for the New

$s_1 = 1.0$ represent the sample deviation for Old

$s_2 = 0.8$ represent the sample deviation for New

$\alpha=0.05$ represent the significance level provided

Confidence =0.95 or 95%

F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:

$F=\frac{s^2_2}{s^2_1}$

Solution to the problem

System of hypothesis

We want to test if the variation for New sample it's lower than the variation for the Old sample, so the system of hypothesis are:

H0: $\sigma^2_2 \geq \sigma^2_1$

H1: $\sigma^2_2$

Calculate the statistic

Now we can calculate the statistic like this:

$F=\frac{s^2_2}{s^2_1}=\frac{0.8^2}{1.0^2}=0.64$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =11-1=10$ and the F statistic have 15 degrees of freedom for the numerator and 10 for the denominator. And the P value is given by:

P value

Since we have a left tailed test the p value is given by:

$p_v =P(F_{15,10}$

And we can use the following excel code to find the p value:"=F.DIST(0.64,15,10,TRUE)"

Conclusion

Since the $p_v > \alpha$ we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation for the New sample it's significantly less than the variation for the Old sample at 5% of significance.

6 0

4 years ago

The number of bacteria present in a laboratory

Reil [10]

Answer:

The answer is B.500

Step-by-step explanation:

The original equation containing unknown variables would be 500(t) (with "t" representing the number of days)

So if you fill the variable in with a 2, that means it's been 2 days with the increase of 500 bacteria each day.

That means the initial number of bacteria must be 500.

If it's been 2 days and you want to determine the bacteria number, then multiply 500 by 2 and you get yourself 1000 bacteria.

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