6*40= 240 + 6*2=12
240+12= 252
Answer:
j = 10
Step-by-step explanation:
You add 7 to both sides then divide both sides by -2
Answer:
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
Step-by-step explanation:
Let 'M' be the event of selecting males n(M) = 12
Number of ways of choosing 3 students From all males and females
![n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276](https://tex.z-dn.net/?f=n%28M%29%20%3D%2028C_%7B3%7D%20%3D%20%5Cfrac%7B28%21%7D%7B%2828-3%29%213%21%7D%20%3D%5Cfrac%7B28%20X%2027%20X%2026%7D%7B3%20X%202%20X%201%20%7D%20%3D%203%2C276)
Number of ways of choosing 3 students From all males
![n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220](https://tex.z-dn.net/?f=n%28M%29%20%3D%2012C_%7B3%7D%20%3D%20%5Cfrac%7B12%21%7D%7B%2812-3%29%213%21%7D%20%3D%5Cfrac%7B12%20X%2011%20X%2010%7D%7B3%20X%202%20X%201%20%7D%20%3D220)
The probability that all are male of choosing '3' students
![P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }](https://tex.z-dn.net/?f=P%28E%29%20%3D%20%5Cfrac%7Bn%28M%29%7D%7Bn%28S%29%7D%20%3D%20%5Cfrac%7B12%20C_%7B3%7D%20%7D%7B28%20C_%7B3%7D%20%7D)
![P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}](https://tex.z-dn.net/?f=P%28E%29%20%3D%20%20%5Cfrac%7B12%20C_%7B3%7D%20%7D%7B28%20C_%7B3%7D%20%7D%20%3D%20%5Cfrac%7B220%7D%7B3276%7D)
P(E) = 0.067 = 6.71%
<u><em>Final answer</em></u>:-
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
<span>-2x-3=y in standard form
=
2x + y = -3
hope it helps</span>
Answer:
ZA = 3 cm
Step-by-step explanation:
Point A is the incenter of the triangle, so segments AX, AY, and AZ are radii of the circle. They are all the same length, given as 3 cm and confirmed by 3-4-5 right triangle AYD.
ZA = 3 cm