Answer:
The mode of the data for Store 2 is greater than the mode of the data for Store 1.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The common difference (d) can be found using the first and 4th terms:
a1 = 3
a4 = a1 +d(4 -1)
-9 = 3 +3d . . . . . simplify
-3 = 1 + d . . . . . . divide by 3
-4 = d . . . . . . . . . subtract 1
Then ...
x = a1 + d = 3 -4 = -1
y = x + d = -1 -4 = -5
The values of x and y are -1 and -5, respectively.
<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
Answer:
The equation relates the variables is y = 8x ⇒ D
Step-by-step explanation:
If x and y vary directly (y ∝ x), then y = k x, where
- k is the constant of variation
- k can be found using the initial value of x and y
∵ The variable x and y vary directly
∴ y ∝ x
→ By using the rule above
∴ y = k x
∵ y = 40 when x = 5
∴ The initial values of x and y are x = 5 and y = 40
→ Substitute them in the equation above to find k
∵ 40 = k(5)
∴ 40 = 5k
→ Divide both sides by 5
∵ 
= 
∴ 8 = k
→ Substitute the value of k in the equation above
∴ y = 8x
∴ The equation relates the variables is y = 8x
