The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
Answer:
44/3
Step-by-step explanation:
V=L*W*H
WH=22/3
V=2*(22/3)
Answer:
(0,3)
Step-by-step explanation:
Step 1: 7x-2y=-6 Step 2: 7x-2y=-6 solve by elimination of the y value
2(8x+y=3)2 +(16x+2y=6)
Step 3: 23x=0, which means <u>x=0</u>
Step 4: subtitute 0 into the equation 8x+y=3
you get 8(0)+y=3, which comes to 0+y=3
you get <u>y=3</u>
therefore the solution to this system is (0,3)
This is the answer and method is above
= <-1 +7t, 4 -t, -5>
Multiply the direction vector by the parameter and add that to the given point.