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3 years ago

Find the square of the following without actual multpliation . 43

Mathematics

1 answer:

devlian [24]3 years ago

3 0

I'll explain how I found it without actual multiplication,

${40}^{2} = 1600 \\ {3}^{2} = 9 \\ 2 \times 40 \times 3 = 240 \\$

So,

${43}^{2} = 1600 + 240 + 9 \\ = 1849$

Hope this will help....

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Unless some of the children who went on Sunday also went on saturday.

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1. y = x2 + 8x + 15 Find the zeros of the function by rewriting the function in intercept form

lubasha [3.4K]

The zeros of given function $y=x^{2}+8 x+15$ is – 5 and – 3

Solution:

$\text { Given, equation is } y=x^{2}+8 x+15$

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as to obtain zeros of function

We know that, intercept form of above equation is $x^{2}+8 x+15=0$

$\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3$

$\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}$

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

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3 years ago

3 2/6 + ( 2 1/6 + 4/6 )

stellarik [79]

Answer:

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3 years ago

Slove for x: x+1/3=1/4

lana [24]

Hey!

To solve this problem, we must subtract one over three from both sides of the equation. This will give us x on its own.

Original Equation :
$x + \frac{1}{3} = \frac{1}{4}$

New Equation {Added Subtract $\frac{1}{3}$ to Both Sides} :
$x + \frac{1}{3} - \frac{1}{3} = \frac{1}{4} - \frac{1}{3}$

Solution {New Equation Solved} :
$x=- \frac{1}{12}$

So, this means that in the equation provided, $x=- \frac{1}{12}$ .

Hope this helps!

- Lindsey Frazier ♥

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Find the square of the following without actual multpliation . 43​

Find the square of the following without actual multpliation . 43