Just want answers/brainliest if right!

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

6 0

Answer:

the first one is D, the second is B, hope this helps

Step-by-step explanation:

You might be interested in

State the necessary value of nn that will make each statement true.<br> 0.0004 × 0.002 = 8 × 10^n

vodka [1.7K]

Answer:

$-7 = n$

Step-by-step explanation:

$0,002 \times 0,0004 = 0,0000008$

$0,0000008 = 8 \times {10}^{-7}$

* You must make sure that you have seven zeros in your decimal.

I am joyous to assist you anytime.

6 0

3 years ago

suppose X and Y are independent random variables, both with normal distributions. If X has a mean of 45 with a standard deviatio

djyliett [7]

Answer:

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu_X = 45, \sigma_X = 4, \mu_Y = 35, \sigma_Y = 3$

What is the probability that a randomly generated value of X is greater than a randomly generated value of Y

This means that the subtraction of X by Y has to be positive.

When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So

$\mu = \mu_X - \mu_Y = 45 - 35 = 0$