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Ganezh [65]
3 years ago
12

If a represents the hypotenuse of this right triangle, which equation could you use to find the value of a?

Mathematics
2 answers:
Sonbull [250]3 years ago
6 0

Answer:

d \: {7}^{2} +  {4}^{2}  = {a}^{2}

Step-by-step explanation:

To find the the hypotenuse of a right triangle, you use the Pythagorean Theorem:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

In the formula above though, c represents the hypotenuse instead of a.

Nitella [24]3 years ago
4 0
The answer is D because they are both legs and you are looking for the hypotenuse
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I would like some assistance please.
butalik [34]

Answer:

2

Step-by-step explanation:

Range is the highest number of plots minus the lowest number, in this case it would be 3-1

6 0
3 years ago
Please explain how to solve for x in the attached photo.
natulia [17]

Answer:

x = 24°

Step-by-step explanation:

the sum of the interior angles in a triangle = 180°

so:

(2x + 5°) + 64° + 3x - 9° = 180°

combine like terms:

5x + 60° = 180°

subtract 60° from each side of the equation:

5x = 120°

x = 24°

5 0
3 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
An easy question all wrong or unhelpful or no-work answers will be reported.
boyakko [2]
Substitution:
2x + (6(1/2x - 6)) = 19
2x + 3x - 36 = 19
5x - 36 = 19
+ 36
5x = 55
÷ 5
x = 11

y = (1/2 × 11) - 6
y = 5.5 - 6
y = -0.5

Elimination:
y = 1/2x - 6
- y
0 = 1/2x - 6 - y
+ 6
1/2x - y = 6

3x - 6y = 36
2x + 6y = 19
(add)
5x = 55
÷ 5
x = 11

y = (1/2 × 11) - 6
y = 5.5 - 6
y = -0.5

I hope this helps! Let me know if you need me to explain why I did some things :)

8 0
3 years ago
Are the data shown in this line plot skewed left, skewed right, or not skewed? skewed right not skewed skewed left Line plot ove
Nimfa-mama [501]
The Answer is Shewed Left
7 0
4 years ago
Read 2 more answers
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