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KiRa [710]
2 years ago
8

PLEASE ANSWER I GIVE BRAINLIEST AND MAX POINTS

Chemistry
1 answer:
d1i1m1o1n [39]2 years ago
7 0

Answer:

I believe the answer is A (changes in air temperature  result in differences in air pressure which causes wind). Hope this helps

Explanation:

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What is the mass of a bar of aluminum with length 5.3cm, width 0.32 cm and height 2.34cm? The density of aluminum is 2.70g/cm3.
Tatiana [17]

Answer:

<h2>mass = 10.72 g</h2>

Explanation:

Density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

Making mass the subject we have

mass = Density \times volume

From the question

Density = 2.70 g/cm³

We assume that the aluminum is a cuboid

and volume of a cuboid is given by

Volume = length × width × height

length = 5.3 cm

width = 0.32 cm

height = 2.34 cm

Volume = 5.3 × 0.32 × 2.34 = 3.97 cm³

Substitute the values into the above and solve for the mass

We have

mass = 2.70 × 3.97

We have the final answer as

<h3>mass = 10.72 g</h3>

Hope this helps you

6 0
3 years ago
Rutherford's experiments on atoms were done on foil made of which of the following elements?
AnnyKZ [126]
A. Gold

Gold is the answer
7 0
3 years ago
Read 2 more answers
What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?
devlian [24]

Answer:

T = 0.182 Kelvin

Explanation:

As we know that

PV = nRT\\

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  

V is the volume in liters

R = 0.08206

Substituting the given values in above equation, we get -

1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\

On rearranging, we get

T = \frac{1.35*50}{1000*0.08206*4.5} \\

T = 0.182 Kelvin

7 0
3 years ago
Radio communications are frequently used in emergencies because
Korvikt [17]

Answer:

they operate on waves

Explanation:

5 0
3 years ago
0.000431 L<br><br> Express your answer as an integer.
Molodets [167]

A whole number, not a fraction, that can be negative, positive or zero are integers. They cannot have decimal places.

Now, converting 0.000431 L to decimal an integer as:

0.000431 L = 431\times 10^{-6} L

Since, 1 L = 10^{6} \mu L

So, 431\times 10^{-6} L\times \frac{10^{6 \mu L}}{1 L} = 431 \mu L.

Hence, the integer value for 0.000431 L is 431 \mu L[.


3 0
3 years ago
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