Answer:
(a). 132 × 10^-9 s = 132 nanoseconds.
(b)..176.5 pico-seconds.
Explanation:
(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;
Speed = [ (8 × R × T)/ Mm × π]^1/2.
Where Mm = molar mass, T = temperature and R = gas constant.
Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.
The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;
Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.
Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.
Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.
Degree of collision = 7.55 × 10^6 s^-1.
Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.
(b). At one bar;
1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.
It's very dangerous to go that deep into the ocean due to the water pressure and the coldness, no human can physically comprehend it, so if you do end up diving that deep into the ocean, you will suffocate, crush to death, or freeze very quickly.
Answer:
CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl
Explanation:
Alkanes react with halogens in the presence of light to yield alkyl halides. The degree of substitution increases as the reaction progresses. The reaction occurs by free radical mechanism.
The reaction between butane and chlorine molecule to yields a monosubstitution product occurs as follows;
CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl
Answer:
9.0 mol
Explanation:
- C₂H₄(g) + 3O₂(g) → 2CO₂ (g) + 2H₂O (g)
In order to <u>convert from moles of CO₂ to moles of O₂</u>, we need to use the <em>stoichiometric coefficients</em> in the balanced reaction. We use a conversion factor that has moles of CO₂ in the denominator and moles of O₂ in the numerator:
- 6.0 mol CO₂ *
= 9.0 mol O₂
5CO2 should be in the blank spot.
the reaction would be 7
