Answer: 
Explanation:

cM 0 0
So dissociation constant will be:

Given: c = 0.15 M
pH = 1.86
= ?
Putting in the values we get:
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![1.86=-log[H^+]](https://tex.z-dn.net/?f=1.86%3D-log%5BH%5E%2B%5D)
![[H^+]=0.01](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.01)
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)


As ![[H^+]=[ClCH_2COO^-]=0.01](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BClCH_2COO%5E-%5D%3D0.01)

![K_a=1.67\times 10^{-3]](https://tex.z-dn.net/?f=K_a%3D1.67%5Ctimes%2010%5E%7B-3%5D)
Thus the vale of
for the acid is 
Answer:
It is <em><u>photosynthesis</u></em><em><u> </u></em><em><u>and </u></em><em><u>transpiration</u></em><em><u> </u></em>
hope it helps
They are atoms. a molecule is made up of atoms.
Answer:
38.4 mol LiOH
Explanation:
Step 1: Write the balanced neutralization equation
2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.
Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂
19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH
H is positive 1 and o is negative 2 so 3+b-6=0 and solve for b to get b=3