I need help solving this system

Mathematics

2 answers:

Irina18 [472]3 years ago

8 0

Answer:

x=3 and y=-7

Step-by-step explanation:

just cause lol

coldgirl [10]3 years ago

3 0

Answer:

(x, y) = (3, -7)

Step-by-step explanation:

$\left \{ {{x - 3y = 24} \atop {5x + 3y = -6}} \right.$

$\left \{ {{x-3y=24} \atop {3y=-6-5x}} \right.$

$x-(-6-5x)=24$

$x=3$

$3y=-6-5(3)$

$y=-7$

$(x,y)=(3,-7)$

CHECKING IF ANSWER IS CORRECT:

$\left \{ {{3-3(-7)=24} \atop {5(3)+3(-7)=-6}} \right.\\\left \{ {{24=24} \atop {-6=-6}} \right. \\(x,y)=(3,-7)$

There is your answer with steps :)

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3 years ago

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What are the domain and range of this function y=(x+3)^2 -5

n200080 [17]

Answer: Choice A

Note: the range should be $[-5, \infty)$ . See explanation below.

===================================================

We can plug in any real number for x to get some output for y. The domain is the set of all real numbers in which we say $(-\infty, \infty)$ which is interval notation. It represents the interval from negative infinity to positive infinity.

The range is the set of possible outputs. The smallest output possible is y = -5 which occurs at the vertex (3,-5). We can get this y value or larger. So we can describe the range as the set of y values such that $y \ge -5$ and that translates to the interval notation $[-5, \infty)$ .

The square bracket says "include this endpoint" while the curved parenthesis says to exclude the endpoint. Your teacher mistakenly wrote $(-5, \infty)$ for choice A, when they should have written $[-5, \infty)$