A solution's hydrogen ion concentration is 1 x 10-5M.<br> What is the pH?

Calorimetry can be used to determine the specific heat capacity of an unknown substance.

Liula [17]

Answer:

TRUE

Explanation:

Main job of calorimeter is to measure energy changes or determine specific heat capacity of different substances. Specific heat is an intensive property (like density, color, etc.) that does not depend on the amount of a substance present. This allows substances to be identified using their specific heat. Thus, calorimeter comes very handy in determining the specfic heat of unknown substance.

4 0

3 years ago

when the sum 4.9965 + 2.11 + 3.887 is calculated, to how many decimal places should the answer be reported?

Murrr4er [49]

Answer:

the correct answer is four decimal places

8 0

3 years ago

Which following statements is true?

Aleksandr-060686 [28]

Answer:

first one

Explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘ C . How many grams of this gasoline would fill a 12.8 gal tan

In-s [12.5K]

To answer this question, you need to know how to convert milliliters into liter then into a gallon. In this question, you are given the gasoline density (0.737g/ml) and the volume (12.8gallon). The information is enough to determine the gas weight. The calculation would be:

Gas weight= density * volume
Gas weight= 0.737g/ml * 12.8 gal * 3.78L/gal * 1000ml/L= 35659.008 grams

6 0

4 years ago

6. Under standard-state conditions, what spontaneous reaction will occur in aqueous solution among the ions Ce4+, Ce3+, Fe3+, an

xz_007 [3.2K]

Answer:

ΔG° = -80.9 KJ

Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

Explanation:

1) Reduction potentials

First of all one should look up the reduction potentials for the species envolved:

$Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

$Fe^{3+} + e$ → $Fe^{2+}$ E°red=0.771V

2) Redox pair

Knowing their reduction pontentials one can determine a redox pair: one species must oxidate while the other is reducing. <u>Remember: the table gives us the reduction potential, so if we want to know the oxidation potential all that has to be done is reverce the equation and change the potencial signal (multiply to -1).</u>

1) $Ce^{4+}$ reduces while $Fe^{2+}$ oxidates

(oxidation) $Fe^{2+}$ → $Fe^{3+} + e$ E°oxi=-0.771V

(reduction) $Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

(overall equation) $Fe^{2+}+Ce^{4+}$ → $Ce^{3+}+Fe^{3+}$ E°=Ereduction + Eoxidation= 1.61 v+(-0.771 v) = 0.839v

The cell potential can also be calculated as the cathode potencial minus the anode potential:

E° = E cathode - E anode =1.61 v - 0.771 v=0.839 v

3) Gibbs free energy and Equilibrium constant

ΔG°=-nFE°, where 'n' is the number of electrons involved in the redox equation, in this case n is 1. 'F' is the Faraday constant, whtch is 96500 C. E° is the standard cell potencial.

ΔG°=-nFE°=-1*96500*0.839

ΔG° = - 80963 J = -80.9 KJ

The Nerst equation gives us the relation of chemical equilibrium and Electric potential.

E=E°- $\frac{RT}{nF} Ln Q$

Where 'R' is the molar gas constant (8.314 J/mol)

It's known that in the equilibrium E=0, so the Nerst equation, at equilibrium, becomes:

E°= $\frac{RT}{nF} Ln K$

Isolating for 'K' gives:

$K=e^{\frac{nFE^{o} }{RT} }$

This shows that 'K' is a fuction of temperature. Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

6 0

4 years ago

A solution's hydrogen ion concentration is 1 x 10-5M. What is the pH?