Answer:
The vehicle travels 56.25 metres in the interval during which body decelerates .
Explanation:
- Initial velocity of vehicle, u = 32 m/s
- Final velocity of vehicle, v = 22 m/s
- Rate of acceleration, a = - 4.8 m/
Let the distance travelled be s .
We have to determine the distance travelled by the vehicle during this time.
The equation of motion is given by
s =
<u>s = 56.25 metres</u>
The vehicle travels 56.25 metres in the interval during which body decelerates .
A thermogram is a representation of infrared electromagnetic waves better known as heat waves. So the correct answer is infrared electromagnetic waves or infrared waves.
Explanation:
The thermogram is associated with infrared camera creates a picture by changing effulgent heat into a symbol which will be displayed on a monitor (and later printed). The infrared energy emitted from the associated object is directly proportional to its temperature. Thus it can be used for temperatures that are accurately measured by the infrared camera.
Answer:
0 kgm/s
Explanation:
The momentum is the product of mass(m) and velocity(v).
Initially the velocity of truck is 0 m/s so the product of mass and velocity becomes 0.
It does not matter what is the weight of truck, because the velocity will make the product of m*v = 0
It does not matter what is the momentum of car.
Answer:
x = D (M/M-m) 2.41
Explanation:
a) Let's apply Newton's second law to find the summation of force, where each force is given by the law of universal gravitation
F = g m₁m₂ / r²
Σ F = 0
F1- F2 = 0
F1 = F2
We set the reference system in the body of greatest mass (M) the planet
F1 = g m₁ M / x²
F2 = G m1 m / (D-x)²
G m₁ M / x² = G m₁ m / (D-x)²
M (D-x)² = m x²
MD² -2MD x + M x² = m x²
x² (M-m) -2MD x + MD² = 0
We solve the second degree equation
x = [2MD ±√ (4M²D² - 4 (M-m) MD²)] / 2 (M-m)
x = {2MD ± 2D √ (M² + (M-m) M)} / 2 (M-m)
x = D {M ± Ra (2M²-mM)} / (M-m)
x = D (M ± M √ (2-m/M)) / (M-m)
x = D (M / (M-m)) (1 ±√ (2-m/M)
Let's analyze this result, the value of M-m >> 1, so if we take the negative root, the value of x would be negative, it is out of the point between the two bodies, so the correct result must be taken with the positive root
x = D (M / (M-m)) (1 + √2)
x = D (M/M-m) 2.41
b) X = 2/3 D
x = D (M/M-m) 2.41
2/3 D = D (M/(M-m)) 2.41
2/3 (M-m) = M 2.41
2/3 M - 2/3 m = 2.41 M
1.743 M = 0.667 m
M/m = 0.667/1.743
M/m = 0.38