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3 years ago

HELP URGENT PLEASE!!!!!!!

Physics

2 answers:

kogti [31]3 years ago

3 0

Answer:

I think c I dont know sorry if I'm wrong

Alecsey [184]3 years ago

3 0

It is C because the North Magnets are stronger than the south magnets and C is the only diagram showing that relation in the middle :)

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The density (mass divided by volume) of water is 1.00 g/cm3 . What is this value in kilograms per cubic meter?

ArbitrLikvidat [17]

1.00g/cm3= 0.001/cm3 = 0.001kg/ 0.000001m3= 1000kg/m3

3 0

4 years ago

A man stands on a platform that is rotating (without friction) with an angular speed of 2.4 rev/s; his arms are outstretched and

andrey2020 [161]

Answer:

The resulting angular speed of the platform is 7.44 rev/s.

Explanation:

Given that,

Speed = 2.4 rev/s

Moment of inertia consist of the man = 6.2 kg-m²

Moment of inertia by the bricks= 2.0 kg-m²

We need to calculate the resulting angular speed of the platform

Using law of conservation of momentum

$L_{1}=L_{2}$

$I\omega_{1}=I\omega_{2}$

$\omega_{2}=\dfrac{I_{1}\omega_{1}}{I_{2}}$

Where,

$I_{1}$ = moment of inertia consist of the man

$I_{2}$ = moment of inertia by the bricks

$\omega_{2}$ = angular speed of platform

Put the value into the formula

$\omega_{2}=\dfrac{6.2\times2.4\times2\pi}{2.0}$

$\omega_{2}=46.74\ rad/s$

$\omega_{2}=\dfrac{46.74}{2\pi}\ rev/s$

$\omega_{2}=7.44\ rev/s$

Hence, The resulting angular speed of the platform is 7.44 rev/s.

4 0

4 years ago

A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont

PIT_PIT [208]

Answer:

$v' = 2.83 m/s$

Explanation:

Velocity of wave in stretched string is given by the formula

$v = \sqrt{\frac{T}{\mu}}$

here we know that

T = 4 N

also we know that linear mass density is given as

$\mu = 1 kg/m$

so we have

$v = \sqrt{\frac{4}{1}} = 2 m/s$

now the tension in the string is double

so the velocity is given as

$v' = \sqrt{\frac{8}{1}} = 2\sqrt2 m/s$

$v' = 2.83 m/s$

4 0

4 years ago

A particle whose mass m=2 kg moves in the xy plane with a constant speed v= 3 m/s in the x direction along the line y = 5. What

Marianna [84]

Answer:

L= 30 kg.m²/s

Explanation:

Given that

m = 2 kg

v= 3 m/s along x direction

y= 5 m

As we know that

Linear momentum P

P = m v

The angular momentum is the moment of linear momentum.

So the angular momentum L

L = m v r

Here r= 5 m

By putting the values

L = m v r

L = 2 x 3 x 5 kg.m²/s

L= 30 kg.m²/s

5 0

3 years ago

Of the following states of motion, the one which requires balanced forces is:

Tanzania [10]

I believe it would be D a change in direction of motion

3 0

3 years ago

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