1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban [17]
3 years ago
12

HELP URGENT PLEASE!!!!!!!

Physics
2 answers:
kogti [31]3 years ago
3 0

Answer:

I think c I dont know sorry if I'm wrong

Alecsey [184]3 years ago
3 0
It is C because the North Magnets are stronger than the south magnets and C is the only diagram showing that relation in the middle :)
You might be interested in
The density (mass divided by volume) of water is 1.00 g/cm3 . What is this value in kilograms per cubic meter?
ArbitrLikvidat [17]
1.00g/cm3= 0.001/cm3 = 0.001kg/ 0.000001m3= 1000kg/m3
3 0
4 years ago
A man stands on a platform that is rotating (without friction) with an angular speed of 2.4 rev/s; his arms are outstretched and
andrey2020 [161]

Answer:

The resulting angular speed of the platform is 7.44 rev/s.

Explanation:

Given that,

Speed = 2.4 rev/s

Moment of inertia consist of the man  = 6.2 kg-m²

Moment of inertia by the bricks= 2.0 kg-m²

We need to calculate the resulting angular speed of the platform

Using law of conservation of momentum

L_{1}=L_{2}

I\omega_{1}=I\omega_{2}

\omega_{2}=\dfrac{I_{1}\omega_{1}}{I_{2}}

Where,

I_{1} = moment of inertia consist of  the man

I_{2} = moment of inertia by the bricks

\omega_{2} = angular speed of platform

Put the value into the formula

\omega_{2}=\dfrac{6.2\times2.4\times2\pi}{2.0}

\omega_{2}=46.74\ rad/s

\omega_{2}=\dfrac{46.74}{2\pi}\ rev/s

\omega_{2}=7.44\ rev/s

Hence, The resulting angular speed of the platform is 7.44 rev/s.

4 0
4 years ago
A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont
PIT_PIT [208]

Answer:

v' = 2.83 m/s

Explanation:

Velocity of wave in stretched string is given by the formula

v = \sqrt{\frac{T}{\mu}}

here we know that

T = 4 N

also we know that linear mass density is given as

\mu = 1 kg/m

so we have

v = \sqrt{\frac{4}{1}} = 2 m/s

now the tension in the string is double

so the velocity is given as

v' = \sqrt{\frac{8}{1}} = 2\sqrt2 m/s

v' = 2.83 m/s

4 0
4 years ago
A particle whose mass m=2 kg moves in the xy plane with a constant speed v= 3 m/s in the x direction along the line y = 5. What
Marianna [84]

Answer:

L= 30  kg.m²/s

Explanation:

Given that

m = 2 kg

v= 3 m/s along x direction

y= 5 m

As we know that

Linear momentum P

P = m v

The angular momentum is the moment of linear momentum.

So the angular momentum L

L = m v r

Here r= 5 m

By putting the values

L = m v r

L = 2 x 3 x 5  kg.m²/s

L= 30  kg.m²/s

5 0
3 years ago
Of the following states of motion, the one which requires balanced forces is:
Tanzania [10]
I believe it would be D a change in direction of motion
3 0
3 years ago
Read 2 more answers
Other questions:
  • What is surface tension and what phase of matter creates it?
    7·1 answer
  • What plate matches almost perfectly with the ring of fire, where most of the world's earthquakes and volcanoes occur? *?
    6·1 answer
  • A waterfall is 145 m high.
    11·2 answers
  • All elements are composed of extremely small particles called
    15·1 answer
  • Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms
    11·1 answer
  • Please answer True or false
    9·1 answer
  • Can I improve the design of my simple machine? How?
    7·1 answer
  • Newton is said to have been inspired by what to describe the theory of gravity?
    11·1 answer
  • The potential energy of an orange on a tree is 6.0 joules. The orange is 5m high. What is the orange's mass?
    6·1 answer
  • A clock in a spaceship is observed to run at a speed of only 3 4 that of a similar clock at rest on earth. how fast (in terms of
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!