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2 years ago

A car has 400 kgm/s worth of momentum and runs into a truck initially at rest. What is the initial momentum of the truck?

Physics

1 answer:

prisoha [69]2 years ago

8 0

Answer:

0 kgm/s

Explanation:

The momentum is the product of mass(m) and velocity(v).

Initially the velocity of truck is 0 m/s so the product of mass and velocity becomes 0.

It does not matter what is the weight of truck, because the velocity will make the product of m*v = 0

It does not matter what is the momentum of car.

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The space shuttle releases a satellite into a circular orbit 630 km above the Earth.

solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

$\displaystyle g=\frac{GM}{r^2}$

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}$

Remove units to make the equation easier to read.

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Multiply the numerator out.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Add the terms in the denominator.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}$

Simplify this equation.

$\displaystyle g=8.11045189 \ \frac{m}{s^2}$

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

$\displaystyle a = \frac{v^2}{r}$

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.

$\displaystyle 8.11045189 \ \frac{m}{s^2} = \frac{v^2}{7008100 \ m}$

Remove units to make the equation easier to read.

$\displaystyle 8.11045189 = \frac{v^2}{7008100}$

Multiply both sides by 7,008,100.

$56838857.89=v^2$

Take the square root of both sides.

$v=7539.154985$

The shuttle should be moving at a velocity of about 7,539 m/s when it is released into the circular orbit above Earth.

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2 years ago

What is necessary for fossil fuels to form? oxygen forming continuously for a long period of time sunlight shining continuously

Oksanka [162]

Heat and pressure acting over a long period of time

4 0

3 years ago

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Which change increases the electric force between objects?

Brrunno [24]

Well, the force is proportional to the product of the charges
on the two objects. So if the objects are already negatively
charged distance between them is unchanged, then adding
electrons to either or both objects would increase the forces
between them.

3 0

2 years ago

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The nutritional label above came from a can of soup how many servings of soup would you need to eat to receive your recommended

Flauer [41]

Each serving gives 3 grams or 12% of daily recommended value. Divide 100% by 12% to get 8.33 servings to obtain the daily recommended value of 25 grams.

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2 years ago

The equation for gear ratio

Ymorist [56]

In a gear train with two gears, the gear ratio is defined as follows
$R= \frac{\omega _A}{\omega _B}$

where $\omega _A$ is the angular velocity of the input gear while $\omega _B$ is the angular velocity of the output gear.

This can be rewritten as a function of the number of teeth of the gears. In fact, the angular velocity of a gear is inversely proportional to the radius r of the gear:
$\omega = \frac{v}{r}$
But the radius is proportional to the number of teeth N of the gear. Therefore we can rewrite the gear ratio also as
$R= \frac{\omega _A}{\omega _B} = \frac{r_B}{r_A} = \frac{N_B}{N_A}$

4 0

3 years ago