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Julli [10]
3 years ago
10

According to Faraday, what is produced by a changing magnetic field?

Physics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

c. Induced voltage.

Explanation:

Faraday's law says

\varepsilon = N \dfrac{d \Phi_B}{dt},

or in words,

<em>"A changing magnetic flux induces an emf (potential difference) in a coil of wire "</em>

This potential difference is induced, and therefore, we can also call it "induced voltage"; Hence, from the choices given, choice C stands correct.

<em>P.S: Another tempting choice is d; however, it is incorrect since induced emf is NOT an electrostatic force.</em>

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Which type of energy is released when a bond between atoms is broken
Murrr4er [49]

Answer: gases

Explanation: because gases move around freely and they would be the only one to make sense because solid are compacted together and liquid are not so fast at moving but gases are wild                                          

dont use this this is a bad explanation

4 0
3 years ago
The mass luminosity relation L  M 3.5 describes the mathematical relationship between luminosity and mass for main sequence sta
ivanzaharov [21]

Answer:

(a) <u>11.3 L</u>

(b) <u>10 M</u>

Explanation:

The mass-luminosity relationship states that:

Luminosity ∝ Mass^3.5

Luminosity = (Constant)(Mass)^3.5

So, in order to find the values of luminosity or mass of different stars, we take the luminosity or mass of sun as reference. Therefore, write the equation for a star and Sun, and divide them to get:

Luminosity of a star/L = (Mass of Star/M)^3.5 ______ eqn(1)

where,

L = Luminosity of Sun

M = mass of Sun

(a)

It is given that:

Mass of Star = 2M

Therefore, eqn (1) implies that:

Luminosity of star/L = (2M/M)^3.5

Luminosity of Star = (2)^3.5 L

<u>Luminosity of Star =  11.3 L</u>

(b)

It is given that:

Luminosity of star = 3160 L

Therefore, eqn (1) implies that:

3160L/L = (Mass of Star/M)^3.5

taking ln on both sides:

ln (3160) = 3.5 ln(Mass of Star/M)

8.0583/3.5 = ln(Mass of Star/M)

Mass of Star/M = e^2.302

<u>Mass of Star = 10 M</u>

3 0
3 years ago
17. Which of the following is the closest weight in newtons of a 7.0-kilogram
marusya05 [52]

Weight = (mass) x (gravity)

Weight = (7.0 kg) x (gravity)

On Earth, where (gravity) is roughly 10 N/kg . . .

Weight = (7.0 kg) x (roughly 10 N/kg)

Weight = roughly 70 Newtons

That's <em>B </em>on Earth.

It would be some other number on other bodies.

4 0
3 years ago
A frictionless pendulum is made with a bob of mass 19.7 kg. The bob is held at height = 0.934 meter above the bottom of its traj
Alika [10]

Answer:

265 J

Explanation:

Energy=PE+KE=mgh+ 0.5mv^{2} where KE is kinetic energy, PE is potential energy, m is the mass of an object, v is the speed, h is the height and g is acceleration due to gravity.

Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

Energy=19.7(9.81*0.934+0.5*2.93^{2})=265.063303\approx 265 J

4 0
2 years ago
What particle is NOT located in the nucleus? A.proton B.electron C.neutron D.quark
baherus [9]
I think it is electron. Electrons are located outside of the nucleus
5 0
3 years ago
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