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Julli [10]
3 years ago
10

According to Faraday, what is produced by a changing magnetic field?

Physics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

c. Induced voltage.

Explanation:

Faraday's law says

\varepsilon = N \dfrac{d \Phi_B}{dt},

or in words,

<em>"A changing magnetic flux induces an emf (potential difference) in a coil of wire "</em>

This potential difference is induced, and therefore, we can also call it "induced voltage"; Hence, from the choices given, choice C stands correct.

<em>P.S: Another tempting choice is d; however, it is incorrect since induced emf is NOT an electrostatic force.</em>

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o-na [289]
The formula PE(Potential Energy)= mgh

4 0
3 years ago
A 2.16 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring const
pochemuha

Answer:

0.15694 m

Explanation:

m = Mass of block = 2.16\times 10^{-2}\ kg

v = Velocity of block = 11.2 m/s

k = Spring constant = 110 N/m

Here the kinetic energy of the fall and spring are conserved

\frac{1}{2}mv^2=\frac{1}{2}kA^2\\\Rightarrow mv^2=kA^2\\\Rightarrow A=\sqrt{\frac{mv^2}{k}}\\\Rightarrow A=\sqrt{\frac{2.16\times 10^{-2}\times 11.2^2}{110}}\\\Rightarrow A=0.15694\ m

The amplitude of the resulting simple harmonic motion is 0.15694 m

3 0
3 years ago
A long solenoid has a radius of 4.0 cm and has 800 turns/m. If the current in the solenoid is increasing at the rate of 3.0 A/s,
kolbaska11 [484]

Answer:

Explanation:

Given that,

Radius of solenoid R = 4cm = 0.04m

Turn per length is N/l = 800 turns/m

The rate at which current is increasing di/dt = 3 A/s

Induced electric field?

At r = 2.2cm=0.022m

µo = 4π × 10^-7 Wb/A•m

The magnetic field inside a solenoid is give as

B = µo•N•I

The value of electric field (E) can

only be a function of the distance r from the solenoid’s axis and it give as,

From gauss law

∮E•dA =qenc/εo

We can find the tangential component of the electric field from Faraday’s law

∮E•dl = −dΦB/dt

We choose the path to be a circle of radius r centered on the cylinder axis. Because all the requested radii are inside the solenoid, the flux-area is the entire πr² area within the loop.

E∮dl = −d/dt •(πr²B)

2πrE = −πr²dB/dt

2πrE = −πr² d/dt(µo•N•I)

2πrE = −πr² × µo•N•dI/dt

Divide both sides by 2πr

E =- ½ r•µo•N•dI/dt

Now, substituting the given data

E = -½ × 0.022 × 4π ×10^-7 × 800 × 3

E = —3.32 × 10^-5 V/m

E = —33.2 µV/m

The magnitude of the electric field at a point 2.2 cm from the solenoid axis is 33.2 µV/m

where the negative sign denotes counter-clockwise electric field when looking along the direction of the solenoid’s magnetic field.

3 0
3 years ago
Read 2 more answers
Ashley, a psychology major, remarks that she has become interested in the study of intelligence. In other words, Ashley is inter
Dimas [21]

Answer: the capacity to understand the world, think rationally, and use resources effectively.

Explanation:

Intelligence refers to higher level abilities, the ability to learn, being creative, having an emotional knowledge, and ability to adapt to different scenarios.

Since Ashley, a psychology major, remarks that she has become interested in the study of intelligence, then Ashley is interested in the capacity to understand the world, think rationally, and use resources effectively.

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3 years ago
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Katarina [22]

Answer:

i think it is d

Explanation:

8 0
3 years ago
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