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mrs_skeptik [129]
3 years ago
15

The standard unit for measuring volume is the--​

Physics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer:

cubic meter

Explanation:

SI units. The base unit of volume in the SI system is the cubic meter. There are 1000 liters per cubic meter, or 1 liter contains the same volume as a cube with sides of length 10cm. A cube with sides of length of 1 cm or 1 cm3 contains a volume of 1 milliliter.

nadya68 [22]3 years ago
4 0

Answer:

Cubic Meter

Explanation:

You might be interested in
The emission line used for zinc determinations in atomic emission spectroscopy is 214 nm. If there are 9.00×1010 atoms of zinc e
KengaRu [80]

Answer:

8.4\cdot 10^{-8}J

Explanation:

The energy emitted by a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

For the photons emitted by the zinc atoms,

\lambda = 214 nm = 214 \cdot 10^{-9} m

So the energy of a single photon emitted is

E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{214\cdot 10^{-9}}=9.3\cdot 10^{-19}J

And since the number of atoms is

N=9.0\cdot 10^{10}

The total energy emitted will be

E=NE_1 = (9.0\cdot 10^{10})(9.3\cdot 10^{-19})=8.4\cdot 10^{-8}J

3 0
4 years ago
Help me<br> please <br> lol<br> ?????
myrzilka [38]

Answer:

150 N= 15 or 150 N= 1.1

Explanation:

What I did was subtract 165kg and 150 N and I divided it too but I got 1.1 so yuhh

4 0
3 years ago
The amount of randomness of the atoms in a system is an indication of the
GuDViN [60]

Answer:

Entropy of the system

Explanation: entropy measures the randomness

4 0
3 years ago
How much work would it take to push two protons very slowly from a separation of 2.00×10−10 m (a typical atomic distance) to 3.0
Deffense [45]

We can visualize the problem in another way, which is equivalent but easier to solve: let's imagine we hold one proton in the same place, and we move the other proton from a distance of 2.00×10−10 m to a distance of 3.00×10−15 m from the first proton. How much work is done?

The work done is equal to the electric potential energy gained by the proton:

W=q \Delta V

where q=1.6 \cdot 10^{-19}C is the charge of the proton and \Delta V is the potential difference between the final position and the initial position of the proton. To calculate this \Delta V, we must calculate the electric potential generated by the proton at rest at the two points, using the formula:

V=k\frac{Q}{r}

where k=9.0 \cdot 10^9 N m^2 C^{-2} is the Coulomb constant and Q is the proton charge. Substituting the initial and final distance of the second proton, we find

V_i = (9.0 \cdot 10^9 )\frac{1.6 \cdot 10^{-19}}{2.0 \cdot 10^{-10}}=7.2 V

V_f = (9.0 \cdot 10^9 )\frac{1.6 \cdot 10^{-19}}{3.0 \cdot 10^{-15}}=4.8 \cdot 10^5 V

Therefore, the work done is

W=q \Delta V=(1.6 \cdot 10^{-19}C)(4.8 \cdot 10^5 V-72 V)=7.7 \cdot 10^{-14} J

6 0
3 years ago
A 1,400 kilogram car travels in a straight line at 10.0 m/sec. what is the momentum
Taya2010 [7]
Momentum = mass * velocity
= 1400 * 10
= 14000 kg m per sec
8 0
4 years ago
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