Hello, there!
The LCM would most likely be:
So, go through all of your factors to find your
of those
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Notice in the first transformation, the y values don't change while the x becomes the opposite, that means the points are reflected across the y axis.
in the second transformation, notice that the x values don't change, the y values are decreased by 6, so all the points are moved straight downward 6 units.
To start with, the pentagon is in the second quadrant. You can tell because all the x values are negative and all the y values are positive. Reflected across the y axis, the image is in the first quadrant. shifted down 6 units, all the vertex are in the fourth quadrant.
If we are to use a single transformation to put the original image in the 4th quadrant, the only choice is b). b) puts the pentagon in the 1st, then in the 4th quadrant.
a) puts it in the 3rd quadrant, c) makes the image go back to where it was d)puts the image in the 1st quadrant.
I tried to answer this question before but I thought the two methods needed to produce two overwrapping images, that is, I thought they needed to end up at exact the same spot. I couldn't figure out how. If the two images just need to be in the same quadrant, my answer is b.
I hope my explanation makes sense. And I hope I am right.
This is a tough one for middle school.
We have been given that Alexis received an 85, 89, and 92 on three tests and we are asked to find out the minimum grade Alexis can score on the fourth test in order to have an average of at least 90.
Let x be marks Alexis can score on the fourth test.
Since we know average is sum of all the numbers divided by number of items. Now we can set our given information in the average formula to get the minimum numbers Alexis can score on the fourth test.
Therefore, the minimum grade Alexis can score on the fourth test is 94, in order to have an average of at least 90.
Answer: 350
Step-by-step explanation:
25 percent of 280 is 70 so it is 350