The answer would be disagree because it you reflected it over the x axis then it would be in the third quadrant
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Answer:
Workdone = 2450Joules
Step-by-step explanation:
Let the top of the aquarium be at height 0.
Let the bottom of the aquarium be at height 1
F = mg = 2p◇x × g
F= 2000◇x × 9.8
F = 19600◇x
Workdone = 19600xdx
Total workdone = Integral (limits 0.5 -0)19600×dx
Total work = [9800x^2]^0.5
Total work= 9800× 0.5^2 = 2450 Joules
you would multiply speed by time
20 feet per second times 10 seconds = 200 feet total
