Sector area = (central angle / 360) * PI * radius^2
sector area = (72 / 360) * PI * radius^2
radius^2 = sector area / [(72 / 360) * PI]
radius^2 = 16.2 * PI / [(1 / 5) * PI]
radius^2 = 16.2 / .2
radius^2 = 81
radius = 9
Source:
http://www.1728.org/radians.htm
Answer:the number of adults that attended the game is 135.
the number of children that attended the game is 31
Step-by-step explanation:
Let x represent the number of adults that attended the game.
Let y represent the number of children that attended the game.
There were 166 paid admissions to a game. This means that
x + y = 166
The price was $2 for adults and $.75 for children. The amount of data taken in was $293.25. This means that
2x + 0.75y = 293.25 - - - - - - - - - - 1
Substituting x = 166 - y into equation 1, it becomes
2(166 - y) + 0.75y = 293.25
332 - 2y + 0.75y = 293.25
- 2y + 0.75y = 293.25 - 332
- 1.25y = - 38.75
y = - 38.75/- 1.25
y = 31
x = 166 - y = x = 166 - 31
x = 135
Answer:
Step-by-step explanation:
We can use the point-slope form given by:
Where <em>m</em> is the slope and (x₁, y₁) is a point.
So, we will substitute -2 for <em>m</em> and (5, 2) for (x₁, y₁). This gives us:
Simplify:
Distribute:
Add 2 to both sides. Hence, our equation is:
Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
57.3 is the answer dididjwkjakz
