Answer:
This shape is somewhat like a square, I believe.
Step-by-step explanation:
1st Point: Inside the I quadrant (the top right), by moving 1 1/2 units to the right on the x-axis, and 4 units up.
2nd Point: Inside the IV quadrant (bottom right), by moving 1 1/2 units to the right on the x-axis, and 8 units down.
3rd Point: Inside the IV quadrant (bottom right), by moving 5 units to the right on the x-axis, and 8 units down.
4th Point: Inside the I quadrant, by moving 5 units to the right on the x-axis, and 4 units up.
40 if you truly really think about it
<u>To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.</u>
Answer:
<em>x = -9</em>
<em>y = 2</em>
Step-by-step explanation:
<u>Solve the system:</u>
2x + 3y = -12 [1]
2x + y = -16 [2]
Subtracting [1] and [2]:
3y - y = -12 + 16
2y = 4
y = 4/2 = 2
From [1]:
2x + 3(2) = -12
2x + 6 = -12
2x = -18
x = -18/2 = -9
Solution:
x = -9
y = 2
The nearest whole number rounds to 6
The nearest tenth rounds to 5.70
The nearest hundredth rounds to 5.70
Complete Question
Which of the following statements are true and which are false? Give reasons for your answers.
(i) Only one line can pass through a single point.
(ii) There are an infinite number of lines which pass through two distinct points.
(iii) A line can be produced indefinitely on both sides.
(iv) If two circles are equal, then their radii are equal.
(v) if AB=PQ and PQ=XY, then AB=XY.
A (i),(ii) - True
(iii),(iv),(v)-False
B(i),(ii),(iii) -True
(iv),(v)-False
C (i),(ii) -False
(iii),(iv),(v)-True
D (i),(ii),(iii) -False
(iv),(v)-True
Answer:
The correct option is C
Step-by-step explanation:
i is false because several lines can pass through a single point
ii is false because only one line can pass through two distinct points
iii is true because you can extend a line from both points (start and end points )
iv is true because when two equal circle are placed together and radius is trace we will discover that they are equal
v is true because from Euclid's First Axiom , if a= c and c = d the a = d
