Add
4
x
4
x
to both sides of the equation.
y
=
−
28
+
4
x
y
=
-
28
+
4
x
Rewrite in slope-intercept form.
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y
=
4
x
−
28
y
=
4
x
-
28
Use the slope-intercept form to find the slope and y-intercept.
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Slope:
4
4
y-intercept:
−
28
-
28
Any line can be graphed using two points. Select two
x
x
values, and plug them into the equation to find the corresponding
y
y
values.
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x
y
2
−
20
3
−
16
x y 2 -20 3 -16
Graph the line using the slope and the y-intercept, or the points.
Slope:
4
4
y-intercept:
−
28
-
28
x
y
2
−
20
3
−
16
x y 2 -20 3 -16
image of graph
y
−
4
x
=
−
2
8
y
-
4
x
=
-
2
8
28
x
28
x
28
x
2
28
x
2
28
x
3
28
x
3
Hope this helps!
Last one should be y=2 +1
The vertex to this question is (6, -31)
collinear points are points in the same line, like
●-----------------●------------------------------------------●
and the line will always be contained by a plane, so since the line is in a plane, all points in it will also be in the same plane, and therefore be coplanar.
The answer to your question is
x<3
