The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x
The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1
<h3>How to determine the quotient</h3>
The quotient expression is given as:
6x^3+2x^2−x divide by x
The above means that,
We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.
So, we have:
6x^3+2x^2−x divide by x = 6x^2 + 2x - 1
Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1
Read more about quotient at:
brainly.com/question/7068223
The labeled angles form a vertical pair, and angles belonging to a vertical pair are congruent. So
Answer:
100°, 104°, 108°, 112°,116°
Step-by-step explanation:
Let the smallest angle be 
. Since, the interior angles are consecutive, the other angles are 
,
,
and 
.
Sum of interior angles = 540°
°
°
°
°
°
Using the value of x to calculate the angles:
°
°
°
°
°
Answer:
-6
Step-by-step explanation:
-2 ^3x3 = 24
-30 + 24 = -6
