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prohojiy [21]
3 years ago
15

Last post as a troll lol, sorry but i need actual help this time.

Chemistry
2 answers:
Wewaii [24]3 years ago
8 0
All I have to say is karma
atroni [7]3 years ago
7 0

Answer:

Lol

Explanation:

lol

nah

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Yanka [14]

Answer:

There are

2.52

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Lipids that are liquid at room temperature are called oils <br> a. True <br> b. False
erica [24]
The answer to your question is false.
4 0
3 years ago
Watching the assignment without knowing how to solve the questions is the worst thing to experience hope someone can help with t
frez [133]

Answer:

- 622.5kJ

Explanation:

1)      2NH3 + 3N2O ----> 4N2 + 3H2O    ΔH° 1= - 1010kJ

-  3 (N2O  + 3H2     --->  N2H4 + H2O    ΔH° 2 = - 317 kJ)

2)      2NH3 + 3N2O ----> 4N2 + 3H2O        ΔH° 1= - 1010kJ

<u>      - 3N2O   - 9 H2     ----> - 3N2H4 - 3H2O      - 3ΔH° 2 = 3*317 kJ</u>

2NH3  + 3N2H4 --->4N2+9H2,     ΔH° 1 -  3*ΔH° 2

2NH3  + 3N2H4  --->4N2+9H2,        ΔH° 1 -  3*ΔH° 2

3) -(2NH3 +1/2O2 ---> N2H4 + H2O,     ΔH°3 = -143 kJ)

   -2NH3 - 1/2O2 ---> - N2H4 - H2O,    - ΔH°3 = 143 kJ

 2NH3  + 3N2H4 --->4N2+9H2,        ΔH° 1 -  3*ΔH° 2

<u>  -2NH3 - 1/2O2              ---> - N2H4 - H2O,             - ΔH°3 = 143 kJ</u>

 4N2H4 + H2O  ---> 4N2  + 9H2 + 1/2O2,    ΔH° 1 -  3*ΔH° 2 - ΔH°3

4)

H2 + 1/2O2 ---> H2O,    ΔH° 4 = - 286 kJ

9*(H2 + 1/2O2 ---> H2O,    ΔH° 4 = - 286 kJ)

9H2+ 9/2 O2 ---> 9H2O,  9*ΔH° 4 = 9*(- 286) kJ

4N2H4 + H2O  ---> 4N2  + 9H2 + 1/2O2,    ΔH° 1 -  3*ΔH° 2 - ΔH°3

<u>9H2+ 9/2 O2    ---> 9H2O,                             9*ΔH° 4 = 9*(- 286) kJ</u>

4N2H4 +4O2 --->4N2+8H2O,         ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

5)

1/4*(4N2H4 +4O2 --->4N2+8H2O,    ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

N2H4 +O2 --->N2+2H2O,        1/4( ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)

6)

N2H4 +O2 --->N2+2,        

1/4( ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)=

=1/4(-1010kJ - 3*(-317kJ) - (-143kJ) + 9*(-286kJ))= - 622.5 kJ

   

7 0
3 years ago
Among the following which solution is the most acidic?
Vika [28.1K]

i think it c i dont know if im right tho.

8 0
3 years ago
How many moles are present in 63.80L of oxygen gas, O2?
matrenka [14]

Answer:

2.85moles of oxygen gas

Explanation:

Given parameters:

Volume of oxygen gas  = 63.8L

Unknown:

Number of moles  = ?

Solution:

We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:

     1 mole of a gas at STP occupies a volume of 22.4L

 So;

       63.8L of oxygen gas will take up a volume of

              \frac{63.8}{22.4}   = 2.85moles of oxygen gas

4 0
3 years ago
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