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3 years ago

What is the number of oxygen atoms in the ring portion of the haworth structure of glucose?

1 answer:

7 0

Answer is: there is one oxygen atom <span>in the ring portion of the Haworth structure of one molecule of glucose, five others oxygen atoms are not in the ring portion.
</span>There are furanose and pyranose Haworth Projections for all aldoses and hexoses, including glucose (C₆H₁₂O₆).
<span>Haworth projection shows a pyranose as a hexagon and a furanose as a pentagon.</span>

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A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?

4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL, we find the volume of water:

$d = \frac{g}{mL} \\\\ V= \frac{g}{d} = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L$

Now, find moles of $CH_{3} OH$ are needed using the molarity equation:

$M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol$

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH, resulting in a concentration of 0,75M

5 0

3 years ago

Margret claimed that she needed 5.45 moles of Potassium Chloride, KCl to complete her experiment. How many grams of KCl does she

zubka84 [21]

Answer:

loiuygfcx

Explanation:

3 0

3 years ago

What will be produced at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2

natita [175]

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

6 0

3 years ago

Is phosphorus dissolving in carbon disulfide a chemical or physical change?

Shkiper50 [21]

Phosphorus dissolving in carbon disulfide is a physical change.

A chemical change results from a chemical reaction, in which the nature of the substance is altered. On the other hand, a physical change is when matter changes forms but not chemical identity.

When phosphorus dissolves in carbon disulfide, it changes its state of aggregation, but not its nature. Thus, this is a physical change.

Phosphorus dissolving in carbon disulfide is a physical change.

You can learn more about physical and chemical changes here: brainly.com/question/13620149

6 0

2 years ago

What is the ionic equation for potassium fluoride and ammonium nitrate

SIZIF [17.4K]

Answer:

kf+Nh4 no3 --> kno3+nh4f

4 0

2 years ago