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8_murik_8 [283]
3 years ago
9

What is the number of oxygen atoms in the ring portion of the haworth structure of glucose?

Chemistry
1 answer:
Aneli [31]3 years ago
7 0
Answer is: there is one oxygen atom <span>in the ring portion of the Haworth structure of one molecule of glucose, five others oxygen atoms are not in the ring portion.
</span>There are furanose and pyranose Haworth Projections for all aldoses and hexoses, including glucose (C₆H₁₂O₆). 
<span>Haworth projection shows a pyranose as a hexagon and a furanose as a pentagon.</span>

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Help please I need it bad
natta225 [31]
= 9.1 × 10^6
(scientific notation)

= 9.1e6
(scientific e notation)

= 9.1 × 10^6
(engineering notation)
(million; prefix mega- (M))

= 9100000
<span>(real number)</span>
5 0
3 years ago
The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i
Rus_ich [418]

Answer: a)  The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) concentration after 8.8 min:

8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}

\log\frac{0.25}{a-x}=0.15

\frac{0.25}{a-x}=1.41

(a-x)=0.17M

b) for concentration to decrease from 0.25M to 0.15M

t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20

t=687s

7 0
3 years ago
Which is the correct answer??
mestny [16]

Answer:

1

Explanation:

8 0
3 years ago
Use the molar heat capacity for aluminum from table 1 to calculate the amount of energy needed to raise the temperature of 260.5
Nimfa-mama [501]
Unfortunately, you failed to include the table 1 from which the molar heat capacity of aluminum could have been obtained. However, as a general rule, the heat needed to raise the temperature of a certain substance by certain degrees is calculated through the equation,
                            H = mcpdT
where H is heat, m is mass, cp is specific heat capacity, and dT is change in temperature. From a reliable source, cp for aluminum is equal to 0.215 cal/g°C. Substituting this to the equation,
                               H = (260.5 g)(0.215 cal/g°C)(125°C - 0)
                                        H = 7000.94 cal
6 0
3 years ago
Ions that have the same electron configuration are called
Katena32 [7]
Such ions are said to be isoelectronic
3 0
3 years ago
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