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Dima020 [189]
3 years ago
12

Which of the following are elements nd which are compounds H2,HCI,Na,Al2O3,H2O

Chemistry
1 answer:
stepan [7]3 years ago
6 0
H2-element
HCl-compound
Na-element
Al2O3-compound
H2O-compound
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Which of these can be classified as a pure substance? Help please
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Answer: The answer is salt

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Which compound is produced when HCl(aq) is neutralized by Ca(OH)2(aq)?
Kisachek [45]
The answer is (1) CaCl2. The reaction formula of this is HCl + Ca(OH)2 = CaCl2 + H2O. This is a reaction of base and acid. So the production is CaCl2 and H2O.
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Why does the sun seem to change position in the sky?
Blababa [14]

The first major contributor to the Sun's apparent motion is the fact that Earth orbits the Sun while tilted on its axis. The Earth's axial tilt of approximately 23.5° ensures that observers at different locations will see the Sun reach higher-or-lower positions above the horizon throughout the year.

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7 0
2 years ago
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In Lab 3, Solubility Rules, students identified ionic salts as soluble or insoluble. The solubility of ionic salts is quantified
Hatshy [7]

Answer:

a) FePO4(s)⇄Fe^3+(aq) + PO4^3-(aq)

b) ZnCO3(s)⇄Zn^2+(aq) + CO3^2-(aq)

c) NH4Cl(s)⇄ NH4^+(aq) + Cl^-(aq)

Explanation:

An ionic solid simply means a solid substance that is held together by ionic bonds. When an ionic substance is added to water, the ions interact with the dipoles in water and is pulled apart to form the constituent cation and anion present in the ionic solid. This is the process that we have referred to as dissolution.

The Ksp of an ionic solid is obtained from the chemical equation that shows the dissolution of an ionic solid in water. The Ksp is actually an equilibrium constant that shows the extent of dissolution of an ionic solid in water.

a) FePO4(s)⇄Fe^3+(aq) + PO4^3-(aq)

b) ZnCO3(s)⇄Zn^2+(aq) + CO3^2-(aq)

c) NH4Cl(s)⇄ NH4^+(aq) + Cl^-(aq)

5 0
3 years ago
1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percen
Naddik [55]

Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol

Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g

% of acetic acid in vinegar=8.64 %

% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0
3 years ago
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