Answer:
Q = 19065.4 J
Explanation:
Q₁ = the required energy for phase change of H₂O from vapor to liquid
Q₁ = mass of H₂O * heat of vaporization
Q₁ = 7.58 g * 2260 J/g
Q₁ = 17130.8 J
Q₂ = energy required to cool the water fro 101°C to 40°C
Q₂ = mass of H₂O * specific heat of H₂O * ΔT
Q₂ = 7.58 × (4.184 J/gC) × (101 - 40)
Q₂ = 1934.6 J
Q = Q₁ + Q₂
Q = (17130.8 + 1934.6) J
Canxi hydroxit
is that a question or statement?
E = 12.92 × 10^(-16) J
Formula for energy is;
E = hc/λ
Where;
h is Planck's constant = 6.63 x 10^(-34) J.s
c is speed of light = 3 × 10^(8) m/s
λ is wavelength = 0.154 nm = 0.154 × 10^(-9) m
E = (6.63 x 10^(-34) × 3 × 10^(8))/(0.154 × 10^(-9))
True
