Calculate the change in heat (Q) that occurs when 7.58grams of steam at 101°C cools to liquid water at 40°C. (cp = 4.184 J/g°C)
1 answer:
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Answer:
The amount of energy transferred to the coin is 28.5 joules.
Explanation:
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Answer: The final temperature of both substances at thermal equilibrium is 301.0 K
Explanation:
As we know that,
.................(1)
where,
q = heat absorbed or released
= mass of gold = 31.5 g
= mass of water = 63.4 g
= final temperature = ?
= temperature of gold =
= temperature of water =
= specific heat of gold =
= specific heat of water=
Now put all the given values in equation (1), we get
The final temperature of both substances at thermal equilibrium is 301.0 K